نمباي

>>> import numpy as np
>>> x = np.array([1, 2, 3])
>>> x
array([1, 2, 3])
>>> y = np.arange(10) # مثل الاقتران نفسه في بايثون ولكن يعطي حقل كمٌخرج
>>> y
array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])

>>> a = np.array([1, 2, 3, 6])
>>> b = np.linspace(0, 2, 4) # يقوم بإنشاء حقل من أربع نقاط تبدأ ب 0 وتنتهي ب 2
>>> c = a - b
>>> c
array([ 1. , 1.33333333, 1.66666667, 4. ])
>>> a**2
array([ 1, 4, 9, 36])

>>> a = np.linspace(-np.pi, np.pi, 100)
>>> b = np.sin(a)
>>> c = np.cos(a)

>>> from numpy.random import rand
>>> from numpy.linalg import solve, inv
>>> a = np.array([[1, 2, 3], [3, 4, 6.7], [5, 9.0, 5]])
>>> a.transpose()
array([[1. , 3. , 5. ],
       [ 2. ,  4. ,  9. ],
       [ 3. ,  6.7,  5.]])
>>> inv(a)
array([[-2.27683616, 0.96045198, 0.07909605],
       [ 1.04519774, -0.56497175,  0.1299435 ],
       [ 0.39548023,  0.05649718, -0.11299435]])
>>> b = np.array([3, 2, 1])
>>> solve(a, b) # solve the equation ax = b
array([-4.83050847, 2.13559322, 1.18644068])
>>> c = rand(3, 3) # create a 3x3 random matrix
>>> c
array([[3.98732789, 2.47702609, 4.71167924],
       [  9.24410671,   5.5240412 ,  10.6468792 ],
       [ 10.38136661,   8.44968437,  15.17639591]])
>>> np.dot(a, c) # matrix multiplication
array([[3.98732789, 2.47702609, 4.71167924],
       [  9.24410671,   5.5240412 ,  10.6468792 ],
       [ 10.38136661,   8.44968437,  15.17639591]])