1958 Wimbledon Championships – Boys' singles

Jimmy Tattersall was the defending champion, but lost to Premjit Lall in the semifinals.

Boys' singles
1958 Wimbledon Championships
ChampionUnited States Butch Buchholz
Runner-upIndia Premjit Lall
Score6–1, 6–3

Butch Buchholz defeated Lall in the final, 6–1, 6–3 to win the boys' singles tennis title at the 1958 Wimbledon Championships.[1]

Draw

Key

Finals

Semifinals Final
          
United States Butch Buchholz 6 8 6
Brazil Ronnie Barnes 8 6 3
United States Butch Buchholz 6 6
India Premjit Lall 1 3
India Premjit Lall 6 6
United Kingdom Jimmy Tattersall 2 2

Top half

First round Second round Quarterfinals Semifinals
United States Butch Buchholz 6 6
Finland Lassie Lincoln 4 1
United States E Buchholz 6 6
Denmark J Leschly 3 1
Lebanon Karim Fawaz 3 2
Denmark Jan Leschly 6 6
United States E Buchholz 6 8 6
Brazil R Barnes 8 6 3
Italy Guiliano Fanfani 0 1
Brazil Ronnie Barnes 6 6 Brazil R Barnes 6 6
Pakistan A Ahmad 0 0 Brazil R Barnes 7 14
Portugal A Abreu 6 3 6 Soviet Union A Potanin 5 12
Monaco C Coste 3 6 4 Portugal A Abreu 1 0
France Alain Bresson 3 6 Soviet Union A Potanin 6 6
Soviet Union Andrei Potanin 6 8

Bottom half

First round Second round Quarterfinals Semifinals
Spain José Luis Arilla 6 6
Socialist Federal Republic of Yugoslavia Srdjan Jelić 0 0 Spain JL Arilla 3 7 6
Sweden Thomas Hallberg 6 6 Sweden T Hallberg 6 5 2
Switzerland Bernard Auberson 1 1 Spain JL Arilla 4 5
Norway TE Vold 1 3 India P Lall 6 7
Republic of Ireland Michael Hickey 6 6 Republic of Ireland M Hickey 0 1
India Premjit Lall 6 6
India P Lall 6 6
United Kingdom J Tattersall 2 2
Poland Piotr Jamroz 7 6
Netherlands Jan Beukers 5 3
Poland P Jamroz 6 2 4
United Kingdom J Tattersall 2 6 6
Austria Peter Pokorny 0 5
United Kingdom Jimmy Tattersall 6 7

References

  1. "Boys' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
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