1970 Pepsi-Cola Masters – Singles

Stan Smith won the singles title at the 1970 Pepsi-Cola Masters. He defeated runner-up Rod Laver, although both had achieved the same number of wins.[1][2]

Singles
1970 Pepsi-Cola Masters
ChampionUnited States Stan Smith
Runner-upAustralia Rod Laver
Score4–6, 6–3, 6–4
Main article: 1970 Pepsi-Cola Masters

Round robin

Key
Australia RosewallSocialist Federal Republic of Yugoslavia FranulovićUnited States AsheUnited States SmithAustralia LaverCzechoslovakia Kodeš
Australia Ken Rosewall6–3, 6–36–3, 6–44–6, 5–66–5, 3–6, 5–66–5, 6–4
Socialist Federal Republic of Yugoslavia Željko Franulović3–6, 3–65–6, 6–3, 2–61–6, 6–5, 1–65–6, 6–3, 2–66–2, 3–6, 6–3
United States Arthur Ashe3–6, 4–66–5, 3–6, 6–23–6, 6–3, 6–53–6, 2–66–3, 4–6, 6–3
United States Stan Smith6–4, 6–56–1, 5–6, 6–16–3, 3–6, 5–64–6, 6–3, 6–46–3, 6–5
Australia Rod Laver5–6, 6–3, 6–56–5, 3–6, 6–26–3, 6–26–4, 3–6, 4–66–4, 6–3
Czechoslovakia Jan Kodeš5–6, 4–62–6, 6–3, 3–63–6, 6–4, 3–63–6, 5–64–6, 3–6

Standings
PlayerRR W-LSets W-LGames W-LStandings
United States Stan Smith
4–1
9–4
71–53
1
Australia Rod Laver
4–1
9–4
69–55
2
Australia Ken Rosewall
3–2
6–4
59–51
3
United States Arthur Ashe
3–2
6–7
58–53
4
Socialist Federal Republic of Yugoslavia Željko Franulović
1–4
5–9
55–70
5
Czechoslovakia Jan Kodeš
0–5
2–10
47–67
6

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

See also

References
  1. John Barrett, ed. (1971). World of Tennis '71. London: Queen Anne Press. p. 134. ISBN 978-0-362-00091-7.
  2. "Smith Bows to Ashe, but Wins Round-Robin Tennis in Tokyo". The New York Times. 15 December 1970.
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