2006 Stella Artois Championships – Doubles

Bob Bryan and Mike Bryan were the defending champions, but lost in the semifinals this year.

Doubles
2006 Queen's Club Championships
Champions
Runners-up
Score6–4, 3–6, [10–8]
Draw24
Main article: 2006 Stella Artois Championships

Paul Hanley and Kevin Ullyett won in the final 6–4, 3–6, [10–8], against Jonas Björkman and Max Mirnyi.

Seeds

All seeds receive a bye into the second round.

  1. United States Bob Bryan / United States Mike Bryan (semifinals)
  2. Sweden Jonas Björkman / Belarus Max Mirnyi (final)
  3. The Bahamas Mark Knowles / Canada Daniel Nestor (semifinals)
  4. Australia Paul Hanley / Zimbabwe Kevin Ullyett (champions)
  5. Australia Stephen Huss / South Africa Wesley Moodie (second round)
  6. Czech Republic František Čermák / Czech Republic Leoš Friedl (quarterfinals)
  7. Zimbabwe Wayne Black / South Africa Jeff Coetzee (quarterfinals)
  8. Australia Wayne Arthurs / United States Justin Gimelstob (quarterfinals)

Draw

Key

Finals
Semifinals Final
          
1
5 64  
4
7 77  
4
6 3 [10]
2
4 6 [8]
3
77 64 [7]
2
65 77 [10]

Top half
First round Second round Quarterfinals Semifinals
1
77 6  
 
6 3 [10]  
60 4  
 
3 6 [6] 1
65 78 [10]
 
4 6 [10] 8
77 66 [7]
 
6 3 [2]  
     
8
w/o    
1
5 64  
4
7 77  
4
3 7 [10]
 
78 6    
6 5 [6]
 
66 3   4
6 6  
 
4 77 [11] 7
4 2  
 
6 61 [9]  
6r    
7
5    

Bottom half
First round Second round Quarterfinals Semifinals
6
w/o    
 
3 62    
     
 
6 77   6
5 4  
 
3 6 [9] 3
7 6  
 
6 2 [11]  
77 66 [11]
3
64 78 [13]
3
77 64 [7]
2
65 77 [10]
5
4 65  
 
5 65   WC
6 77  
WC
7 77   WC
64 2  
 
3 63   2
77 6  
WC
6 77   WC
77 4 [6]
2
64 6 77
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