2014 Sacramento Challenger – Doubles

John-Patrick Smith and Matt Reid were the defending champions, however they chose not to participate with each other. Smith partners Adam Hubble, whilst Reid partners Jose Statham.

Doubles
2014 Sacramento Challenger
ChampionsAustralia Adam Hubble
Australia John-Patrick Smith
Runners-upCanada Peter Polansky
Canada Adil Shamasdin
Score6–3, 6–2

Adam Hubble and John-Patrick Smith won the title by defeating Peter Polansky and Adil Shamasdin 6–3, 6–2 in the final.

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 New Zealand M Daniell
New Zealand A Sitak
6 77
WC South Africa R de Voest
United States M Seeberger
1 64 1 New Zealand M Daniell
New Zealand A Sitak
2 78 [10]
Q United Kingdom L Broady
Australia J Thompson
3 3   Australia A Bolt
Canada F Dancevic
6 66 [4]
  Australia A Bolt
Canada F Dancevic
6 6 1 New Zealand M Daniell
New Zealand A Sitak
4 77 [14]
PR/4 United States S Bangoura
United States T Sandgren
1 4 PR Australia A Hubble
Australia J-P Smith
6 65 [16]
PR Australia A Hubble
Australia J-P Smith
6 6 PR Australia A Hubble
Australia J-P Smith
6 66 [10]
  Italy T Fabbiano
Italy L Vanni
3 4   Netherlands T de Bakker
Netherlands W Koolhof
4 78 [8]
  Netherlands T de Bakker
Netherlands W Koolhof
6 6 PR Australia A Hubble
Australia J-P Smith
6 6
  United States A Kuznetsov
United States V Mirzadeh
5 6 [10] 2 Canada P Polansky
Canada A Shamasdin
3 2
WC United States A Halebian
United States D Novikov
7 4 [2]   United States A Kuznetsov
United States V Mirzadeh
6 4 [7]
WC United States D Nguyen
United States E Quigley
7 6 WC United States D Nguyen
United States E Quigley
4 6 [10]
LL Austria S Bader
United States Erik Elliott
5 4 WC United States D Nguyen
United States E Quigley
4 2
  Republic of Ireland J Cluskey
Republic of Ireland J McGee
6 4 [8] 2 Canada P Polansky
Canada A Shamasdin
6 6
PR Australia M Reid
New Zealand J Statham
3 6 [10]   Australia M Reid
New Zealand J Statham
2 4
  United States D Kudla
United States R Williams
66 0 2 Canada P Polansky
Canada A Shamasdin
6 6
2 Canada P Polansky
Canada A Shamasdin
77 6

References

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