2020 Cleveland Open – Doubles

Romain Arneodo and Andrei Vasilevski were the defending champions[1] but chose not to defend their title.

Doubles
2020 Cleveland Open
Champions	Treat Huey Nathaniel Lammons
Runners-up	Luke Saville John-Patrick Smith
Score	7–5, 6–2

Treat Huey and Nathaniel Lammons won the title after defeating Luke Saville and John-Patrick Smith 7–5, 6–2 in the final.

Seeds

Luke Saville / John-Patrick Smith (final)
Nam Ji-sung / Song Min-kyu (quarterfinals)
Luis David Martínez / Miguel Ángel Reyes-Varela (first round)
Dennis Novikov / Gonçalo Oliveira (first round)

Draw

Key

	First round							Quarterfinals							Semifinals							Final

	1	L Saville J-P Smith	7⁷	6
	WC	C Harrison R Harrison	6⁴	3				1	L Saville J-P Smith	6	6
		S Ofner R Quiroz	4	2					J Cerretani M Cressy	4	4
		J Cerretani M Cressy	6	6											1	L Saville J-P Smith	6⁶	6	[10]
	3	LD Martínez MÁ Reyes-Varela	6⁸	5												L Glasspool A Lawson	7⁸	4	[6]
		R Cid Subervi S Mansouri	7¹⁰	7					R Cid Subervi S Mansouri	3	6⁸
		L Glasspool A Lawson	6	6					L Glasspool A Lawson	6	7¹⁰
		R Gonzales R Roelofse	3	4																		1	L Saville J-P Smith	5	2
		D Popko A Tabilo	4	5																			T Huey N Lammons	7	6
		T Huey N Lammons	6	7					T Huey N Lammons	7¹⁰	6
	WC	Ian Dempster K Lovett	6	4	[10]			WC	I Dempster K Lovett	6⁸	4
	4	D Novikov G Oliveira	4	6	[8]											T Huey N Lammons	6	7⁷
		N Pasha Ma Redlicki	2	1												R Galloway H Hach Verdugo	3	6⁵
		R Galloway H Hach Verdugo	6	6					R Galloway H Hach Verdugo	6	7¹⁰
	WC	James Hopper Nico Mostardi	4	4				2	J-s Nam M-k Song	3	6⁸
	2	J-s Nam M-k Song	6	6

References

"Cleveland Open is returning to Cleveland Racquet Club in February". Crain's Cleveland Business. September 20, 2019.

External links

Main draw

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