Bilinski dodecahedron

In geometry, the Bilinski dodecahedron is a convex polyhedron with twelve congruent golden rhombus faces. It has the same topology but a different geometry than the face-transitive rhombic dodecahedron. It is a parallelohedron.

(Animation)

(Dimensioning)

Orthogonal projections that look like golden rhombohedra

Other orthogonal projections

Pairs of golden rhombohedra
(Animations)

See details

History

This shape appears in a 1752 book by John Lodge Cowley, labeled as the dodecarhombus.[1][2] It is named after Stanko Bilinski, who rediscovered it in 1960.[3] Bilinski himself called it the rhombic dodecahedron of the second kind.[4] Bilinski's discovery corrected a 75-year-old omission in Evgraf Fedorov's classification of convex polyhedra with congruent rhombic faces.[5]

Definition and properties

Definition

The Bilinski dodecahedron is formed by gluing together twelve congruent golden rhombi. These are rhombi whose diagonals are in the golden ratio:

\varphi ={{1+{\sqrt {5}}} \over 2}\approx 1.618~034.

The graph of the resulting polyhedron is isomorphic to the graph of the rhombic dodecahedron, but the faces are oriented differently: one pair of opposite rhombi has their long and short diagonals reversed, relatively to the orientation of the corresponding rhombi in the rhombic dodecahedron.

Symmetry

Because of its reversal, the Bilinski dodecahedron has a lower order of symmetry; its symmetry group is that of a rectangular cuboid: $D 2h, [2,2], (*222),$ of order 8. This is a subgroup of octahedral symmetry; its elements are: three 2-fold symmetry axes, three symmetry planes (which are also the axial planes of this solid), and a center of inversion symmetry. The rotation group of the Bilinski dodecahedron is $D 2, [2,2] +, (222),$ of order 4.

Vertices

Like the rhombic dodecahedron, the Bilinski dodecahedron has eight vertices of degree 3 and six of degree 4. It has two apices on the vertical axis, and four vertices on each axial plane. But due to the reversal, its non-apical vertices form two squares (red and green) and one rectangle (blue), and its fourteen vertices in all are of four different kinds:

two degree-4 apices surrounded by four acute face angles (vertical-axis vertices, black in first figure);
four degree-4 vertices surrounded by three acute and one obtuse face angles (horizontal-axial-plane vertices, blue in first figure);
four degree-3 vertices surrounded by three obtuse face angles (one vertical-axial-plane vertices, red in first figure);
four degree-3 vertices surrounded by two obtuse and one acute face angles (other vertical-axial-plane vertices, green in first figure).

Faces

The supplementary internal angles of a golden rhombus are:[6]

acute angle:

\alpha =\arctan 2\approx 63.434~949^{\circ };

obtuse angle:

\beta =\pi -\arctan 2\approx 116.565~051^{\circ }.

The faces of the Bilinski dodecahedron are twelve congruent golden rhombi; but due to the reversal, they are of three different kinds:

eight apical faces with all four kinds of vertices,
two side faces with alternate blue and red vertices (front and back in first figure),
two side faces with alternating blue and green vertices (left and right in first figure).

(See also the figure with edges and front faces colored.)

Edges

The 24 edges of the Bilinski dodecahedron have the same length; but due to the reversal, they are of four different kinds:

four apical edges with black and red vertices (in first figure),
four apical edges with black and green vertices (in first figure),
eight side edges with blue and red vertices (in first figure),
eight side edges with blue and green vertices (in first figure).

(See also the figure with edges and front faces colored.)

Bilinski dodecahedron (standing on one of its reversal side faces) with edges and front faces colored by their symmetry positions

Cartesian coordinates, lengths

The vertices of the Bilinski dodecahedron with thickness 2 can have Cartesian coordinates:

degree	color	coordinates
3	red	( $0, \pm1, \pm1$ )
3	green	( $\pm φ, 0, \pm φ$ )
4	blue	( $\pm φ, \pm1, 0$ )
4	black	( $0, 0, \pm φ 2$ )

where $φ$ is the golden ratio.

The Bilinski dodecahedron of this size has:

length of longest body diagonal (i.e. lying on opposite black degree-4 vertices):

2~\varphi ^{2}=3+{\sqrt {5}}\approx 5.236~068;

length of shorter body diagonals (i.e. lying on opposite blue degree-4 vertices):

2{\sqrt {2+\varphi }}={\sqrt {2\left(5+{\sqrt {5}}\right)}}\approx 3.804~226;

edge length:

{\sqrt {2+\varphi }}={\sqrt {\frac {5+{\sqrt {5}}}{2}}}\approx 1.902~113.

In families of polyhedra

The Bilinski dodecahedron is a parallelohedron; thus it is also a space-filling polyhedron, and a zonohedron.

Relation to rhombic dodecahedron

In a 1962 paper,[7] H. S. M. Coxeter claimed that the Bilinski dodecahedron could be obtained by an affine transformation from the rhombic dodecahedron, but this is false. For:

In the rhombic dodecahedron: every long body diagonal (i.e. lying on opposite degree-4 vertices) is parallel to the short diagonals of four faces.

In the Bilinski dodecahedron: the longest body diagonal (i.e. lying on opposite black degree-4 vertices) is parallel to the short diagonals of two faces, and to the long diagonals of two other faces; the shorter body diagonals (i.e. lying on opposite blue degree-4 vertices) are not parallel to the diagonal of any face.[5]

In any affine transformation of the rhombic dodecahedron: every long body diagonal (i.e. lying on opposite degree-4 vertices) remains parallel to four face diagonals, and these remain of the same (new) length.

Zonohedra with golden rhombic faces

A Bilinski dodecahedron is a zonohedron; it has four sets of six parallel edges. Contracting any set of six parallel edges to zero length produces a golden rhombohedron.

The Bilinski dodecahedron can be formed from the rhombic triacontahedron (another zonohedron, with thirty congruent golden rhombic faces) by removing or collapsing two zones or belts of ten and eight golden rhombic faces with parallel edges. Removing only one zone of ten faces produces the rhombic icosahedron. Removing three zones of ten, eight, and six faces produces a golden rhombohedron.[4][5] Thus removing a zone of six faces from the Bilinski dodecahedron produces a golden rhombohedron. The Bilinski dodecahedron can be dissected into four golden rhombohedra, two of each type.[8]

The vertices of the zonohedra with golden rhombic faces can be computed by linear combinations of two to six generating edge vectors with coefficients 0 or 1.[9] A belt $m n$ means a belt representing $n$ directional vectors, and containing $m$ coparallel edges with same length. The Bilinski dodecahedron has four belts of six coparallel edges.

These zonohedra are projection envelopes of the hypercubes, with $n$ -dimensional projection basis, with golden ratio ( $φ$ ). For $n = 6,$ the specific basis is:

x = (1, φ, 0,-1, φ, 0),

y = (φ, 0, 1, φ, 0,-1),

z = (0, 1, φ, 0,-1, φ).

For $n = 5,$ the basis is the same with the sixth column removed. For $n = 4,$ the fifth and sixth columns are removed.

Zonohedra with golden rhombic faces
Solid name	Triacontahedron	Icosahedron	Dodecahedron	Hexahedron (acute/obtuse)	Rhombus (2-faced)
Full symmetry	I_h (order 120)	D_5d (order 20)	D_2h (order 8)	D_3d (order 12)	D_2h (order 8)
n Belts of (2(n−1))_n // edges[10]	6 belts of 10₆ // edges	5 belts of 8₅ // edges	4 belts of 6₄ // edges	3 belts of 4₃ // edges	2 belts of 2₂ // edges
n(n−1) Faces[11]	30	20 (−10)	12 (−8)	6 (−6)	2 (−4)
2n(n−1) Edges[12]	60	40 (−20)	24 (−16)	12 (−12)	4 (−8)
n(n−1)+2 Vertices[13]	32	22 (−10)	14 (−8)	8 (−6)	4 (−4)
Solid image
Parallel edges image
Dissection	10 + 10	5 + 5	2 + 2
Projective n-cube	6-cube	5-cube	4-cube	3-cube	2-cube
Projective n-cube image

References

Hart, George W. (2000), "A color-matching dissection of the rhombic enneacontahedron", Symmetry: Culture and Science, 11 (1–4): 183–199, MR 2001417.
Cowley, John Lodge (1752), Geometry Made Easy; Or, a New and Methodical Explanation of the Elements of Geometry, London, Plate 5, Fig. 16. As cited by Hart (2000).
Bilinski, S. (1960), "Über die Rhombenisoeder", Glasnik Mat. Fiz. Astr., 15: 251–263, Zbl 0099.15506.
Cromwell, Peter R. (1997), Polyhedra: One of the most charming chapters of geometry, Cambridge: Cambridge University Press, p. 156, ISBN 0-521-55432-2, MR 1458063.
Grünbaum, Branko (2010), "The Bilinski dodecahedron and assorted parallelohedra, zonohedra, monohedra, isozonohedra, and otherhedra", The Mathematical Intelligencer, 32 (4): 5–15, doi:10.1007/s00283-010-9138-7, hdl:1773/15593, MR 2747698, S2CID 120403108.
Ogawa, Tohru (January 1987), "Symmetry of three-dimensional quasicrystals", Materials Science Forum, 22–24: 187–200, doi:10.4028/www.scientific.net/msf.22-24.187, S2CID 137677876. See in particular table 1, p. 188.
Coxeter, H. S. M. (1962), "The classification of zonohedra by means of projective diagrams", Journal de Mathématiques Pures et Appliquées, 41: 137–156, MR 0141004. Reprinted in Coxeter, H. S. M. (1968), Twelve geometric essays, Carbondale, Ill.: Southern Illinois University Press, MR 0310745 (The Beauty of Geometry. Twelve Essays, Dover, 1999, MR 1717154).
"Golden Rhombohedra", CutOutFoldUp, retrieved 2016-05-26
Let V denote the number of vertices and e_k denote the k-th generating edge vector, where 1 ≤ k ≤ n;
for 2 ≤ n ≤ 3, V = card(𝒫 {e₁,...,e_n}) = 2ⁿ;
for 4 ≤ n ≤ 6, V < 2ⁿ, because some of the linear combinations of four to six generating edge vectors with coefficients 0 or 1 end strictly inside the golden rhombic zonohedron.
Let e_k denote the k-th generating edge vector, where 1 ≤ k ≤ n;
example: e₁ and e_n correspond to a pair of opposite rhombi, ..., e_n−1 and e_n correspond to a different pair of opposite rhombi; in all: e_n is represented in n−1 different pairs of opposite rhombi, so in 2(n−1) different rhombi; these form a strip; this is closed, otherwise it would be infinite; so e_n is represented in 2(n−1) different (coparallel) edges of this belt.
A golden rhombic zonohedron has each pair of opposite rhombi corresponding to two among n generating edge vectors, so it has:
F = 2×(ⁿ₂) = n(n−1) faces.
A golden rhombic zonohedron has each face lying on four edges, and each edge lying in two faces, so it has:
E = 4F/2 = 2F = 2n(n−1) edges.
A golden rhombic zonohedron has:
V = E−F+2 = 2n(n−1)−n(n−1)+2 = n(n−1)+2 vertices.

External links

VRML model, George W. Hart: www.georgehart.com/virtual-polyhedra/vrml/rhombic_dodecahedron_of_second_kind.wrl
animation and coordinates, David I. McCooey: dmccooey.com/polyhedra/BilinskiDodecahedron.html
A new Rhombic Dodecahedron from Croatia!, YouTube video by Matt Parker

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[1] Hart, George W. (2000), "A color-matching dissection of the rhombic enneacontahedron", Symmetry: Culture and Science, 11 (1–4): 183–199, MR 2001417.

[2] Cowley, John Lodge (1752), Geometry Made Easy; Or, a New and Methodical Explanation of the Elements of Geometry, London, Plate 5, Fig. 16. As cited by Hart (2000).

[3] Bilinski, S. (1960), "Über die Rhombenisoeder", Glasnik Mat. Fiz. Astr., 15: 251–263, Zbl 0099.15506.

[crom-4] Cromwell, Peter R. (1997), Polyhedra: One of the most charming chapters of geometry, Cambridge: Cambridge University Press, p. 156, ISBN 0-521-55432-2, MR 1458063.

[grun-5] Grünbaum, Branko (2010), "The Bilinski dodecahedron and assorted parallelohedra, zonohedra, monohedra, isozonohedra, and otherhedra", The Mathematical Intelligencer, 32 (4): 5–15, doi:10.1007/s00283-010-9138-7, hdl:1773/15593, MR 2747698, S2CID 120403108.

[ogawa-6] Ogawa, Tohru (January 1987), "Symmetry of three-dimensional quasicrystals", Materials Science Forum, 22–24: 187–200, doi:10.4028/www.scientific.net/msf.22-24.187, S2CID 137677876. See in particular table 1, p. 188.

[7] Coxeter, H. S. M. (1962), "The classification of zonohedra by means of projective diagrams", Journal de Mathématiques Pures et Appliquées, 41: 137–156, MR 0141004. Reprinted in Coxeter, H. S. M. (1968), Twelve geometric essays, Carbondale, Ill.: Southern Illinois University Press, MR 0310745 (The Beauty of Geometry. Twelve Essays, Dover, 1999, MR 1717154).

[8] "Golden Rhombohedra", CutOutFoldUp, retrieved 2016-05-26

[9] Let V denote the number of vertices and e_k denote the k-th generating edge vector, where 1 ≤ k ≤ n;
for 2 ≤ n ≤ 3, V = card(𝒫 {e₁,...,e_n}) = 2ⁿ;
for 4 ≤ n ≤ 6, V < 2ⁿ, because some of the linear combinations of four to six generating edge vectors with coefficients 0 or 1 end strictly inside the golden rhombic zonohedron.

[10] Let e_k denote the k-th generating edge vector, where 1 ≤ k ≤ n;
example: e₁ and e_n correspond to a pair of opposite rhombi, ..., e_n−1 and e_n correspond to a different pair of opposite rhombi; in all: e_n is represented in n−1 different pairs of opposite rhombi, so in 2(n−1) different rhombi; these form a strip; this is closed, otherwise it would be infinite; so e_n is represented in 2(n−1) different (coparallel) edges of this belt.

[11] A golden rhombic zonohedron has each pair of opposite rhombi corresponding to two among n generating edge vectors, so it has:
F = 2×(ⁿ₂) = n(n−1) faces.

[12] A golden rhombic zonohedron has each face lying on four edges, and each edge lying in two faces, so it has:
E = 4F/2 = 2F = 2n(n−1) edges.

[13] A golden rhombic zonohedron has:
V = E−F+2 = 2n(n−1)−n(n−1)+2 = n(n−1)+2 vertices.