Four Pillars of Destiny

Four Pillars of Destiny can be dated back to the Han Dynasty, but it was not systematic as it is known today.

• In the time of Tang dynasty, Lǐ Xūzhōng (Chinese: 李虛中) reorganized this concept, and used each of the two sexagenary cycle characters assigned to a person's birth year, month and date to predict one's personality and future. This was called the "Three Pillars of Destiny", and after this theory become more and more popular.[1]

• During Song Dynasty, Xú Zi Píng (Chinese:徐子平) reformed Lǐ Xūzhōng's "Three Pillars of Destiny" by adding the "birth time" as the fourth pillar. This meant adding another 2 sexagenary cycle characters to the person's fate pillars, from six characters into eight characters, which made the forecast accuracy seem much higher and making the Three Pillars of Destiny more useful. Therefore, people regarded Xú Zi Píng as the creator of a solid foundation for the Four Pillars of Destiny.[1]

Days, hours, months, and years are all assigned one of the ten Celestial Stems (Chinese: 十天干) and one of the twelve Terrestrial Branches (Chinese: 十二地支) in the sexagenary cycle. A person's fortune is determined by looking up the branch and stem characters for each of these four parts of their birth time, with relation to the 10-year luck cycle (Chinese: 十年大运).

The schools are the Scholarly School (學院派, Xué Yuàn Pài) and the Professional School (江湖派, Jiāng Hú Pài).

The Scholarly School began with Xú Zi Píng (徐子平) at the beginning of the Song Dynasty. Xú founded the pure theoretical basis of the system. Representatives of this school and their publications include:

Song Dynasty (宋)

• Sān Mìng Yuān Yuán 三命渊源, by Xú Dà Shēng 徐大升
• Yuān Hǎi Zi Píng 淵海子平, compiled by Xú Dà Shēng 徐大升 (styled Zi Píng 子平)

Ming Dynasty (明)

• Dī Tiān Suǐ 滴天髓
• Sān Mìng Tōng Kuài 三命通會, by Wàn Mín Yīng 万民英
• Míng Wàn Yù Wú 明萬育吾
• Míng Liú Jī 明劉基

Qing Dynasty (清)

• Mìng Lǐ Yuē Yán 命理約言, by Chén Sù Ān 陈素庵
• Mìng Lǐ Tàn Yuán 命理探源, by Yuán Shù Shān 袁树珊

The problem of periodicity of four pillars is a problem in calendrical arithmetics, but most of fortune tellers are unable to handle the mathematics correctly. Hee[2] for example, proposed that it takes 240 years for a given four-pillar quadruplet to repeat itself. In p. 22, Hee wrote,

... because of the numerous possible combinations, it takes 60 years for the same set of year pillars to repeat itself (by comparison, as set of month pillars repeats itself after just five years). Therefore, if you have a certain day and time, the set of four pillars will repeat itself in 60 years. However, since the same day may not appear in exactly the same month – and even if it is in the same month, the day may not be found in the same half month – it takes 240 years before the identical four pillars appear again ...

Hee's proposal is incorrect and can be easily refuted by a counterexample. For example, the four-pillar quadruplets for 1984-3-18 and 2044-3-3 are exactly the same (i.e. 甲子-丁卯-辛亥-xx) and they are spaced only by 60 years. But the next iso-quadruplet will reappear only after 360 years (on 2404-4-5). Furthermore, a periodicity of 1800 years is needed to order to match both sexagenary cycle and the Gregorian cycle. For example, 4-3-18, 1980-3-18, and 3964-3-18 share the same four-pillar quadruplet.

The solution to the iso-Gregorian quadruplet is a Diophantine problem. Suppose that the gap, ${\displaystyle g}$, between two successive four-pillar quadruplet is irregular and it is given by ${\displaystyle g=60(365\lambda _{1}+\lambda _{2})}$ and suppose that ${\displaystyle f}$ and ${\displaystyle f+g'}$ are two successive rata die numbers with identical Gregorian month and day, then it can be shown that the interval ${\displaystyle g'}$ is given by${\displaystyle g'=365\lambda _{3}+366\lambda _{4}.}$For ${\displaystyle g}$ and ${\displaystyle g'}$ to coincide, we need solve

${\displaystyle 60(365\lambda _{1}+\lambda _{2})=365\lambda _{3}+366\lambda _{4},}$

to which one of the solution is ${\displaystyle (\lambda _{1},\lambda _{2},\lambda _{3},\lambda _{4})=(33,8,1575,402).}$ Therefore ${\displaystyle g=60(365\times 33+8)=723180}$days or about 1800 Gregorian years.

• Destiny
• Symbolic stars
• Astrology
• Zǐ wēi dòu shù—a Chinese lunar astrological method
• Wikibooks: Ba Zi