Disproportionation

The first disproportionation reaction to be studied in detail was:

${\displaystyle {\ce {2 Sn^2+ -> Sn^4+ + Sn}}}$

This was examined using tartrates by Johan Gadolin in 1788. In the Swedish version of his paper he called it söndring.[4][5]

• Mercury(I) chloride disproportionates upon UV-irradiation:

${\displaystyle {\ce {Hg2Cl2 -> HgCl2 + Hg}}}$

• Phosphorous acid disproportionates upon heating to give phosphoric acid and phosphine:

${\displaystyle {\ce {4 H3PO3 -> 3 H3PO4 + PH3}}}$

• Desymmetrizing reactions are sometimes referred to as disproportionation, as illustrated by the thermal degradation of bicarbonate:

${\displaystyle {\ce {2 HCO3- -> CO3^{2}- + H2CO3}}}$

The oxidation numbers remain constant in this acid-base reaction.

• Another variant on disproportionation is radical disproportionation, in which two radicals form an alkene and an alkane.

${\displaystyle {\ce {2CH3-{\underset {^{\bullet }}{C}}H2->{H2C=CH2}+H3C-CH3}}}$

• Disproportionation of sulfur intermediates by microorganisms are widely observed in sediments.[6][7][8][9]

1. ${\displaystyle {\ce {4 S^0 + 4 H2O -> 3 H2S + SO4^{2}- + 2 H+}}}$
2. ${\displaystyle {\ce {3 S^0 + 2 FeOOH -> SO4^{2}- + 2FeS + 2 H+}}}$
3. ${\displaystyle {\ce {4 SO3^{2}- + 2 H+ -> H2S + SO4^{2}-}}}$

• Chlorine gas reacts with dilute sodium hydroxide to form sodium chloride, sodium chlorate and water. The ionic equation for this reaction is as follows:[10]
  $${\displaystyle {\ce {3Cl2 + 6 OH- -> 5 Cl- + ClO3- + 3 H2O}}}$$

  
  • The chlorine reactant is in oxidation state 0. In the products, the chlorine in the Cl⁻ ion has an oxidation number of −1, having been reduced, whereas the oxidation number of the chlorine in the ClO₃⁻ ion is +5, indicating that it has been oxidized.
• Decompositions of numerous interhalogen compounds involve disproportionation. Bromine fluoride undergoes disproportionation reaction to form bromine trifluoride and bromine:[11]
  $${\displaystyle {\ce {3 BrF -> BrF3 + Br2}}}$$

  
• The dismutation of superoxide free radical to hydrogen peroxide and oxygen, catalysed in living systems by the enzyme superoxide dismutase:
  $${\displaystyle {\ce {2 O2- + 2H+ -> H2O2 + O2}}}$$

  
  The oxidation state of oxygen is −1/2 in the superoxide free radical anion, −1 in hydrogen peroxide and 0 in dioxygen.
• In the Cannizzaro reaction, an aldehyde is converted into an alcohol and a carboxylic acid. In the related Tishchenko reaction, the organic redox reaction product is the corresponding ester. In the Kornblum–DeLaMare rearrangement, a peroxide is converted to a ketone and an alcohol.
• The disproportionation of hydrogen peroxide into water and oxygen catalysed by either potassium iodide or the enzyme catalase:
  $${\displaystyle {\ce {2 H2O2 -> 2 H2O + O2}}}$$

  
• In the Boudouard reaction, carbon monoxide disproportionates to carbon and carbon dioxide. The reaction is for example used in the HiPco method for producing carbon nanotubes, high-pressure carbon monoxide disproportionates when catalysed on the surface of an iron particle:
  $${\displaystyle {\ce {2 CO -> C + CO2}}}$$

  
• Nitrogen has oxidation state +4 in nitrogen dioxide, but when this compound reacts with water, it forms both nitric acid and nitrous acid, where nitrogen has oxidation states +5 and +3 respectively:
  $${\displaystyle {\ce {2NO2 + H2O -> HNO3 + HNO2}}}$$

  
• Dithionite undergoes acid hydrolysis to thiosulfate and bisulfite:[12]
  $${\displaystyle {\ce {2{S2O4^{2-}}+H2O->{S2O3^{2-}}+2HSO3-}}}$$

  
• Dithionite also undergoes alkaline hydrolysis to sulfite and sulfide:[12]
  $${\displaystyle {\ce {3 Na2S2O4 + 6 NaOH -> 5 Na2SO3 + Na2S + 3 H2O}}}$$

  
• Dithionate is prepared on a larger scale by oxidizing a cooled aqueous solution of sulfur dioxide with manganese dioxide:[13]
  $${\displaystyle {\ce {2 MnO2 + 3 SO2 -> MnS2O6 + MnSO4}}}$$

  

In free-radical chain-growth polymerization, chain termination can occur by a disproportionation step in which a hydrogen atom is transferred from one growing chain molecule to another which produces two dead (non-growing) chains.[14]

-------CH₂–CHX^• + -------CH₂–CHX^• → -------CH=CHX + -------CH₂–CH₂X

^• indicates radicals.

In 1937, Hans Adolf Krebs, who discovered the citric acid cycle bearing his name, confirmed the anaerobic dismutation of pyruvic acid into lactic acid, acetic acid and CO₂ by certain bacteria according to the global reaction:[15]

2CH₃COCOOH + H₂O -> CH₃CH(OH)COOH + CH₃COOH + CO₂

The dismutation of pyruvic acid in other small organic molecules (ethanol + CO₂, or lactate and acetate, depending on the environmental conditions) is also an important step in fermentation reactions. Fermentation reactions can also be considered as disproportionation or dismutation biochemical reactions. Indeed, the donor and acceptor of electrons in the redox reactions supplying the chemical energy in these complex biochemical systems are the same organic molecules simultaneously acting as reductant or oxidant.

Another example of biochemical dismutation reaction is the disproportionation of acetaldehyde into ethanol and acetic acid.[16]

While in respiration electrons are transferred from substrate (electron donor) to an electron acceptor, in fermentation part of the substrate molecule itself accepts the electrons. Fermentation is therefore a type of disproportionation, and does not involve an overall change in oxidation state of the substrate. Most of the fermentative substrates are organic molecules. However, a rare type of fermentation may also involve the disproportionation of inorganic sulfur compounds in certain sulfate-reducing bacteria.[17]

Sulfur isotopes of sediments are often measured for studying environments in the Earth's past (Paleoenvironment). Disproportionation of sulfur intermediates, being one of the processes affecting sulfur isotopes of sediments, has drawn attention from Geoscientists for studying the redox conditions in the oceans in the past.

Sulfate-reducing bacteria fractionate sulfur isotopes as they take in sulfate and produce sulfide. Prior to 2010s, it was thought that sulfate reduction could fractionate sulfur isotopes up to 46 permil[18] and fractionation larger than 46 permil recorded in sediments must be due to disproportionation of sulfur intermediates in the sediment. This view has changed since the 2010s.[19] As substrates for disproportionation are limited by the product of sulfate reduction, the isotopic effect of disproportionation should be less than 16 permil in most sedimentary settings.[9]

Disproportionation can be carried out by microorganisms obligated to disproportionation or microorganisms that can carry out sulfate reduction as well. Common substrates for disproportionation include elemental sulfur, thiosulfate and sulfite.[9]

• Dismutase
• Oxidoreductase
• Fermentation (biochemistry)