Hartland Township, Freeborn County, Minnesota

According to the United States Census Bureau, the township has a total area of 35.9 square miles (93 km²), of which 35.9 square miles (93 km²) is land and 0.04 square miles (0.10 km²) (0.08%) is water.

As of the census[1] of 2000, there were 298 people, 112 households, and 82 families residing in the township. The population density was 8.3 inhabitants per square mile (3.2/km²). There were 120 housing units at an average density of 3.3 per square mile (1.3/km²). The racial makeup of the township was 96.31% White, 0.34% Native American, 2.35% from other races, and 1.01% from two or more races. Hispanic or Latino of any race were 2.68% of the population.

There were 112 households, out of which 36.6% had children under the age of 18 living with them, 71.4% were married couples living together, 1.8% had a female householder with no husband present, and 25.9% were non-families. 22.3% of all households were made up of individuals, and 8.9% had someone living alone who was 65 years of age or older. The average household size was 2.66 and the average family size was 3.16.

In the township the population was spread out, with 25.2% under the age of 18, 8.7% from 18 to 24, 24.8% from 25 to 44, 23.2% from 45 to 64, and 18.1% who were 65 years of age or older. The median age was 40 years. For every 100 females, there were 114.4 males. For every 100 females age 18 and over, there were 120.8 males.

The median income for a household in the township was $38,125, and the median income for a family was $41,964. Males had a median income of $31,875 versus $17,500 for females. The per capita income for the township was $15,913. About 7.2% of families and 9.5% of the population were below the poverty line, including 8.6% of those under the age of eighteen and 7.1% of those 65 or over.