Herbrand's theorem

Let

${\displaystyle (\exists y_{1},\ldots ,y_{n})F(y_{1},\ldots ,y_{n})}$

be a formula of first-order logic with ${\displaystyle F(y_{1},\ldots ,y_{n})}$ quantifier-free, though it may contain additional free variables. This version of Herbrand's theorem states that the above formula is valid if and only if there exists a finite sequence of terms ${\displaystyle t_{ij}}$, possibly in an expansion of the language, with

${\displaystyle 1\leq i\leq r}$ and ${\displaystyle 1\leq j\leq n}$,

such that

${\displaystyle F(t_{11},\ldots ,t_{1n})\vee \ldots \vee F(t_{r1},\ldots ,t_{rn})}$

is valid. If it is valid, it is called a Herbrand disjunction for

${\displaystyle (\exists y_{1},\ldots ,y_{n})F(y_{1},\ldots ,y_{n}).}$

Informally: a formula ${\displaystyle A}$ in prenex form containing only existential quantifiers is provable (valid) in first-order logic if and only if a disjunction composed of substitution instances of the quantifier-free subformula of ${\displaystyle A}$ is a tautology (propositionally derivable).

The restriction to formulas in prenex form containing only existential quantifiers does not limit the generality of the theorem, because formulas can be converted to prenex form and their universal quantifiers can be removed by Herbrandization. Conversion to prenex form can be avoided, if structural Herbrandization is performed. Herbrandization can be avoided by imposing additional restrictions on the variable dependencies allowed in the Herbrand disjunction.

A proof of the non-trivial direction of the theorem can be constructed according to the following steps:

1. If the formula ${\displaystyle (\exists y_{1},\ldots ,y_{n})F(y_{1},\ldots ,y_{n})}$ is valid, then by completeness of cut-free sequent calculus, which follows from Gentzen's cut-elimination theorem, there is a cut-free proof of ${\displaystyle \vdash (\exists y_{1},\ldots ,y_{n})F(y_{1},\ldots ,y_{n})}$.
2. Starting from leaves and working downwards, remove the inferences that introduce existential quantifiers.
3. Remove contraction inferences on previously existentially quantified formulas, since the formulas (now with terms substituted for previously quantified variables) might not be identical anymore after the removal of the quantifier inferences.
4. The removal of contractions accumulates all the relevant substitution instances of ${\displaystyle F(y_{1},\ldots ,y_{n})}$ in the right side of the sequent, thus resulting in a proof of ${\displaystyle \vdash F(t_{11},\ldots ,t_{1n}),\ldots ,F(t_{r1},\ldots ,t_{rn})}$, from which the Herbrand disjunction can be obtained.

However, sequent calculus and cut-elimination were not known at the time of Herbrand's proof, and Herbrand had to prove his theorem in a more complicated way.

• Herbrand's theorem has been extended to higher-order logic by using expansion-tree proofs.[3] The deep representation of expansion-tree proofs corresponds to a Herbrand disjunction, when restricted to first-order logic.
• Herbrand disjunctions and expansion-tree proofs have been extended with a notion of cut. Due to the complexity of cut-elimination, Herbrand disjunctions with cuts can be non-elementarily smaller than a standard Herbrand disjunction.
• Herbrand disjunctions have been generalized to Herbrand sequents, allowing Herbrand's theorem to be stated for sequents: "a Skolemized sequent is derivable if and only if it has a Herbrand sequent".

• Herbrand structure
• Herbrand interpretation
• Herbrand universe
• Compactness theorem

• Buss, Samuel R. (1995), "On Herbrand's Theorem", in Maurice, Daniel; Leivant, Raphaël (eds.), Logic and Computational Complexity, Lecture Notes in Computer Science, Berlin, New York: Springer-Verlag, pp. 195–209, ISBN 978-3-540-60178-4.