Method overriding

Ada provides method overriding by default. To favor early error detection (e.g. a misspelling), it is possible to specify when a method is expected to be actually overriding, or not. That will be checked by the compiler.

  type T is new Controlled with ......;
  procedure Op(Obj: in out T; Data: in Integer);

  type NT is new T with null record;
  overriding    -- overriding indicator
  procedure Op(Obj: in out NT; Data: in Integer);
  overriding    -- overriding indicator
  procedure Op(Obj: in out NT; Data: in String);
  -- ^ compiler issues an error: subprogram "Op" is not overriding

C# does support method overriding, but only if explicitly requested using the modifiers override and virtual or abstract.

abstract class Animal
{
    public          string Name { get; set; }
    // Methods
    public          void   Drink();
    public virtual  void   Eat();
    public          void   Go();
}

class Cat : Animal
{
    public new      string Name { get; set; }
    // Methods
    public          void   Drink();  // Warning: hides inherited drink(). Use new
    public override void   Eat();    // Overrides inherited eat().
    public new      void   Go();     // Hides inherited go().
}

When overriding one method with another, the signatures of the two methods must be identical (and with same visibility). In C#, class methods, indexers, properties and events can all be overridden.

Non-virtual or static methods cannot be overridden. The overridden base method must be virtual, abstract, or override.

In addition to the modifiers that are used for method overriding, C# allows the hiding of an inherited property or method. This is done using the same signature of a property or method but adding the modifier new in front of it.[6]

In the above example, hiding causes the following:

Cat cat = new Cat();

cat.Name = …;             // accesses Cat.Name
cat.Eat();                // calls Cat.Eat()
cat.Go();                 // calls Cat.Go()
((Animal)cat).Name = …;   // accesses Animal.Name!
((Animal)cat).Eat();      // calls Cat.Eat()!
((Animal)cat).Go();       // calls Animal.Go()!

C++ does not have the keyword super that a subclass can use in Java to invoke a superclass version of a method that it wants to override. Instead, the name of the parent or base class is used followed by the scope resolution operator. For example, the following code presents two classes, the base class Rectangle, and the derived class Box. Box overrides the Rectangle class's Print method, so as also to print its height.[7]

#include <iostream>

//---------------------------------------------------------------------------
class Rectangle {
 public:
  Rectangle(double l, double w) : length_(l), width_(w) {}
  virtual void Print() const;

 private:
  double length_;
  double width_;
};

//---------------------------------------------------------------------------
void Rectangle::Print() const {
  // Print method of base class.
  std::cout << "Length = " << length_ << "; Width = " << width_;
}

//---------------------------------------------------------------------------
class Box : public Rectangle {
 public:
  Box(double l, double w, double h) : Rectangle(l, w), height_(h) {}
  void Print() const override;

 private:
  double height_;
};

//---------------------------------------------------------------------------
// Print method of derived class.
void Box::Print() const {
  // Invoke parent Print method.
  Rectangle::Print();
  std::cout << "; Height = " << height_;
}

The method Print in class Box, by invoking the parent version of method Print, is also able to output the private variables length and width of the base class. Otherwise, these variables are inaccessible to Box.

The following statements will instantiate objects of type Rectangle and Box, and call their respective Print methods:

int main(int argc, char** argv) {
  Rectangle rectangle(5.0, 3.0);

  // Outputs: Length = 5.0; Width = 3.0
  rectangle.Print();

  Box box(6.0, 5.0, 4.0);

  // The pointer to the most overridden method in the vtable in on Box::print,
  // but this call does not illustrate overriding.
  box.Print();

  // This call illustrates overriding.
  // outputs: Length = 6.0; Width = 5.0; Height= 4.0
  static_cast<Rectangle&>(box).Print();
}

In C++11, similar to Java, a method that is declared final in the super class cannot be overridden; also, a method can be declared override to make the compiler check that it overrides a method in the base class.

In Delphi, method overriding is done with the directive override, but only if a method was marked with the dynamic or virtual directives.

The inherited reserved word must be called when you want to call super-class behavior

type
  TRectangle = class
  private
    FLength: Double;
    FWidth: Double;
  public
    property Length read FLength write FLength;
    property Width read FWidth write FWidth;

    procedure Print; virtual;
  end;

  TBox = class(TRectangle)
  public
    procedure Print; override;
  end;

In Eiffel, feature redefinition is analogous to method overriding in C++ and Java. Redefinition is one of three forms of feature adaptation classified as redeclaration. Redeclaration also covers effecting, in which an implementation is provided for a feature which was deferred (abstract) in the parent class, and undefinition, in which a feature that was effective (concrete) in the parent becomes deferred again in the heir class. When a feature is redefined, the feature name is kept by the heir class, but properties of the feature such as its signature, contract (respecting restrictions for preconditions and postconditions), and/or implementation will be different in the heir. If the original feature in the parent class, called the heir feature's precursor, is effective, then the redefined feature in the heir will be effective. If the precursor is deferred, the feature in the heir will be deferred.[8]

The intent to redefine a feature, as message in the example below, must be explicitly declared in the inherit clause of the heir class.

class
    THOUGHT
feature
    message
            -- Display thought message
        do
            print ("I feel like I am diagonally parked in a parallel universe.%N")
        end
end

class
    ADVICE
inherit
    THOUGHT
        redefine
            message
        end
feature
    message
            -- Precursor
        do
            print ("Warning: Dates in calendar are closer than they appear.%N")
        end
end

In class ADVICE the feature message is given an implementation that differs from that of its precursor in class THOUGHT.

Consider a class which uses instances for both THOUGHT and ADVICE:

class
    APPLICATION
create
    make
feature 
    make
            -- Run application.
        do
            (create {THOUGHT}).message;
            (create {ADVICE}).message
        end
end

When instantiated, class APPLICATION produces the following output:

I feel like I am diagonally parked in a parallel universe.
Warning: Dates in calendar are closer than they appear.

Within a redefined feature, access to the feature's precursor can be gained by using the language keyword Precursor. Assume the implementation of {ADVICE}.message is altered as follows:

    message
            -- Precursor
        do
            print ("Warning: Dates in calendar are closer than they appear.%N")
            Precursor
        end

Invocation of the feature now includes the execution of {THOUGHT}.message, and produces the following output:

Warning: Dates in calendar are closer than they appear.
I feel like I am diagonally parked in a parallel universe.

In Java, when a subclass contains a method with the same signature (name and parameter types) as a method in its superclass, then the subclass's method overrides that of the superclass. For example:

class Thought {
    public void message() {
        System.out.println("I feel like I am diagonally parked in a parallel universe.");
    }
}

public class Advice extends Thought {
    @Override  // @Override annotation in Java 5 is optional but helpful.
    public void message() {
        System.out.println("Warning: Dates in calendar are closer than they appear.");
    }
}

Class Thought represents the superclass and implements a method call message() . The subclass called Advice inherits every method that could be in the Thought class. Class Advice overrides the method message() , replacing its functionality from Thought .

Thought parking = new Thought();
parking.message();  // Prints "I feel like I am diagonally parked in a parallel universe."

Thought dates = new Advice();  // Polymorphism
dates.message();  // Prints "Warning: Dates in calendar are closer than they appear."

When a subclass contains a method that overrides a method of the superclass, then that (superclass's) overridden method can be explicitly invoked from within a subclass's method by using the keyword super .[3] (It cannot be explicitly invoked from any method belongings to a class that is unrelated to the superclass.) The super reference can be

public class Advice extends Thought {
      @Override
      public void message() {
          System.out.println("Warning: Dates in calendar are closer than they appear.");
          super.message();  // Invoke parent's version of method.
      }

There are methods that a subclass cannot override. For example, in Java, a method that is declared final in the super class cannot be overridden. Methods that are declared private or static cannot be overridden either because they are implicitly final. It is also impossible for a class that is declared final to become a super class.[9]

In Kotlin we can simply override a function like this (note that the function must be open ):

fun main() {
    val p = Parent(5)
    val c = Child(6)
    p.myFun()
    c.myFun()
}

open class Parent(val a : Int) {
    open fun myFun() = println(a)
}

class Child(val b : Int) : Parent(b) {
    override fun myFun() = println("overrided method")
}

In Python, when a subclass contains a method that overrides a method of the superclass, you can also call the superclass method by calling super(Subclass, self).method[10] instead of self.method. Example:

class Thought:
    def __init__(self) -> None:
        print("I'm a new object of type Thought!")
    def message(self) -> None:
        print("I feel like I am diagonally parked in a parallel universe.")

class Advice(Thought):
    def __init__(self) -> None:
        super(Advice, self).__init__()
    def message(self) -> None:
        print("Warning: Dates in calendar are closer than they appear")
        super(Advice, self).message()

t = Thought()
# "I'm a new object of type Thought!"
t.message()
# "I feel like I am diagonally parked in a parallel universe.

a = Advice()
# "I'm a new object of type Thought!"
a.message()
# "Warning: Dates in calendar are closer than they appear"
# "I feel like I am diagonally parked in a parallel universe.

# ------------------
# Introspection:

isinstance(t, Thought)
# True

isinstance(a, Advice)
# True

isinstance(a, Thought)
# True

In Ruby when a subclass contains a method that overrides a method of the superclass, you can also call the superclass method by calling super in that overridden method. You can use alias if you would like to keep the overridden method available outside of the overriding method as shown with 'super_message' below.

Example:

class Thought
  def message
    puts "I feel like I am diagonally parked in a parallel universe."
  end
end

class Advice < Thought
  alias :super_message :message
  def message
    puts "Warning: Dates in calendar are closer than they appear"
    super
  end
end