Mazeppa (1909 film)
Mazeppa (Russian: Мазепа) is a 1909 Russian drama film directed by Vasili Goncharov.[1][2][3][4]
| Mazeppa | |
|---|---|
| Russian: Мазепа | |
| Directed by | Vasili Goncharov |
| Written by | |
| Produced by | Aleksandr Khanzhonkov |
| Starring |
|
| Cinematography | Vladimir Siversen |
| Country | Russian Empire |
| Language | Russian |
Plot
The film tells about the Hetman named Mazepa, who is in love with Kochubey's daughter, Maria, and asks her father for consent to marry her, but his father refuses him. This does not stop them and they run away...[5]
Cast
- Vasili Stepanov as Kochubey
- Andrey Gromov as Mazepa
- Raisa Reyzen as Maria
- Antonina Pozharskaya as Maria's mother[6]
References
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