Right circular cylinder

Bases: the two parallel and congruent circles of the bases;[4]

Axis: the line determined by the two points of the centers of the cylinder's bases;[1]

Height: the distance between the two planes of the cylinder's bases;[2]

Geratrices: the line segments parallel to the axis and that have ends at the points of the bases' circles.[2]

Illustration of a cylinder and the planification of its lateral surface.

The lateral surface of a right cylinder is the meeting of the generatrices.[3] It can be obtained by the product between the length of the circumference of the base and the height of the cylinder. Therefore, the lateral surface area is given by:

• ${\textstyle L=2\pi rh}$.[2]

Where:

• ${\displaystyle L\,}$represents the lateral surface area of the cylinder;
• ${\displaystyle \pi \,}$is approximately 3.14;
• ${\displaystyle r\,}$is the distance between the lateral surface of the cylinder and the axis, i.e. it is the value of the radius of the base;
• ${\displaystyle h\,}$is the height of the cylinder;
• ${\displaystyle 2\pi r}$ is the length of the circumference of the base, since ${\displaystyle \pi ={\frac {C}{2r}}}$, that is, ${\displaystyle C=2\pi r}$.[5]

Note that in the case of the right circular cylinder, the height and the generatrix have the same measure, so the lateral area can also be given by:

• ${\displaystyle L=2\pi rg}$.

The area of the base of a cylinder is the area of a circle (in this case we define that the circle has a radius with measure ${\displaystyle r}$):

• ${\displaystyle B=\pi r^{2}}$.

To calculate the total area of a right circular cylinder, you simply add the lateral area to the area of the two bases:

• ${\displaystyle A=L+2\cdot B}$.

Replacing ${\displaystyle L=2\pi rh}$ and ${\displaystyle B=\pi r^{2}}$, we have:

• ${\displaystyle A=2\pi rh+2\pi r^{2}}$ ${\displaystyle \Rightarrow A=2\pi r(h+r)}$

or even

• ${\displaystyle A=2\pi r(g+r)}$.

Illustration of a cylinder and a prism, both with height ${\displaystyle h}$. Note that the area of the base of each solid is ${\displaystyle S}$.

Through Cavalieri's principle, which defines that if two solids of the same height, with congruent base areas, are positioned on the same plane, such that any other plane parallel to this plane sections both solids, determining from this section two polygons with the same area,[6] then the volume of the two solids will be the same, we can determine the volume of the cylinder.

This is because the volume of a cylinder can be obtained in the same way as the volume of a prism with the same height and the same area of the base. Therefore, simply multiply the area of the base by the height:

• ${\displaystyle V=B\cdot h}$.

Since the area of a circle of radius ${\displaystyle r\,}$, which is the base of the cylinder, is given by ${\displaystyle B=\pi r^{2}}$ it follows that:

• ${\displaystyle V=\pi r^{2}h}$[2]

or even

• ${\displaystyle V=\pi r^{2}g}$.

Illustration of a cylinder circumscribed by a sphere of radius ${\displaystyle r}$. Note that the cylinder is equilateral.

The equilateral cylinder is characterized by being a right circular cylinder in which the diameter of the base is equal to the value of the height (geratrix).[4]

Then, assuming that the radius of the base of an equilateral cylinder is ${\displaystyle r\,}$ then the diameter of the base of this cylinder is ${\displaystyle 2r\,}$ and its height is ${\displaystyle 2r\,}$.[4]

Its lateral area can be obtained by replacing the height value by ${\displaystyle 2r}$:

• ${\displaystyle L=2\pi r\cdot 2r}$ ${\displaystyle \Rightarrow L=4\pi r^{2}}$.

The result can be obtained in a similar way for the total area:

• ${\displaystyle T=2\pi r(h+r)}$ ${\displaystyle \Rightarrow T=2\pi r(2r+r)}$ ${\displaystyle \Rightarrow T=2\pi r\cdot 3r}$ ${\displaystyle \Rightarrow T=6\pi r^{2}}$.

For the equilateral cylinder it is possible to obtain a simpler formula to calculate the volume. Simply substitute the radius and height measurements defined earlier into the volume formula for a straight circular cylinder:

• ${\displaystyle V=\pi r^{2}\cdot h}$ ${\displaystyle \Rightarrow V=\pi r^{2}\cdot 2r}$ ${\displaystyle \Rightarrow V=2\pi r^{3}}$

It is the intersection between a plane containing the axis of the cylinder and the cylinder.[4]

In the case of the right circular cylinder, the meridian section is a rectangle, because the generatrix is perpendicular to the base. The equilateral cylinder, on the other hand, has a square meridian section because its height is congruent to the diameter of the base.[1][4]

• 
  Bale of straw.
• 
  Titanium cylinder.
• 
  Candle.

• Cylinder
• Geometry
• Solid geometry

• Balestri, Rodrigo (2016). Matemática: interação e tecnologia (in Portuguese) (2 ed.). São Paulo: Leya.
• Conexões com a matemática (in Portuguese) (1 ed.). São Paulo: Moderna. 2010.
• Dolce, Osvaldo; Pompeo, José Nicolau (2013). Fundamentos da matemática elementar 9: geometria plana (in Portuguese) (9 ed.). São Paulo: Atual.
• Dolce, Osvaldo; Pompeo, José Nicolau (2005). Fundamentos da matemática elementar, 10: geometria espacial, posição e métrica (in Portuguese). São Paulo: Atual.
• Giovanni, José Ruy; Giovanni Jr., José Ruy; Bonjorno, José Roberto (2011). Matemática fundamental: uma nova abordagem (in Portuguese). São Paulo: FTD.
• Paiva, Manoel (2004). Matemática (in Portuguese) (1 ed.). São Paulo: Moderna.