Algebraic integer

The following are equivalent definitions of an algebraic integer. Let K be a number field (i.e., a finite extension of ${\displaystyle \mathbb {Q} }$, the field of rational numbers), in other words, ${\displaystyle K=\mathbb {Q} (\theta )}$ for some algebraic number ${\displaystyle \theta \in \mathbb {C} }$ by the primitive element theorem.

• α ∈ K is an algebraic integer if there exists a monic polynomial ${\displaystyle f(x)\in \mathbb {Z} [x]}$ such that f(α) = 0.
• α ∈ K is an algebraic integer if the minimal monic polynomial of α over ${\displaystyle \mathbb {Q} }$ is in ${\displaystyle \mathbb {Z} [x]}$.
• α ∈ K is an algebraic integer if ${\displaystyle \mathbb {Z} [\alpha ]}$ is a finitely generated ${\displaystyle \mathbb {Z} }$-module.
• α ∈ K is an algebraic integer if there exists a non-zero finitely generated ${\displaystyle \mathbb {Z} }$-submodule ${\displaystyle M\subset \mathbb {C} }$ such that αM ⊆ M.

Algebraic integers are a special case of integral elements of a ring extension. In particular, an algebraic integer is an integral element of a finite extension ${\displaystyle K/\mathbb {Q} }$.

• The only algebraic integers which are found in the set of rational numbers are the integers. In other words, the intersection of ${\displaystyle \mathbb {Q} }$ and A is exactly ${\displaystyle \mathbb {Z} }$. The rational number a/b is not an algebraic integer unless b divides a. Note that the leading coefficient of the polynomial bx − a is the integer b. As another special case, the square root ${\displaystyle {\sqrt {n}}}$ of a nonnegative integer n is an algebraic integer, but is irrational unless n is a perfect square.
• If d is a square-free integer then the extension ${\displaystyle K=\mathbb {Q} ({\sqrt {d}}\,)}$ is a quadratic field of rational numbers. The ring of algebraic integers O_K contains ${\displaystyle {\sqrt {d}}}$ since this is a root of the monic polynomial x² − d. Moreover, if d ≡ 1 mod 4, then the element ${\textstyle {\frac {1}{2}}(1+{\sqrt {d}}\,)}$ is also an algebraic integer. It satisfies the polynomial x² − x + 1/4(1 − d) where the constant term 1/4(1 − d) is an integer. The full ring of integers is generated by ${\displaystyle {\sqrt {d}}}$ or ${\textstyle {\frac {1}{2}}(1+{\sqrt {d}}\,)}$ respectively. See Quadratic integer for more.
• The ring of integers of the field ${\displaystyle F=\mathbb {Q} [\alpha ]}$, α = ³√m, has the following integral basis, writing m = hk² for two square-free coprime integers h and k:[1]
  $${\displaystyle {\begin{cases}1,\alpha ,{\dfrac {\alpha ^{2}\pm k^{2}\alpha +k^{2}}{3k}}&m\equiv \pm 1{\bmod {9}}\\1,\alpha ,{\dfrac {\alpha ^{2}}{k}}&{\text{otherwise}}\end{cases}}}$$

  
• If ζ_n is a primitive nth root of unity, then the ring of integers of the cyclotomic field ${\displaystyle \mathbb {Q} (\zeta _{n})}$ is precisely ${\displaystyle \mathbb {Z} [\zeta _{n}]}$.
• If α is an algebraic integer then β = ⁿ√α is another algebraic integer. A polynomial for β is obtained by substituting xⁿ in the polynomial for α.

• If P(x) is a primitive polynomial which has integer coefficients but is not monic, and P is irreducible over ${\displaystyle \mathbb {Q} }$, then none of the roots of P are algebraic integers (but are algebraic numbers). Here primitive is used in the sense that the highest common factor of the coefficients of P is 1; this is weaker than requiring the coefficients to be pairwise relatively prime.

• The sum, difference and product of two algebraic integers is an algebraic integer. In general their quotient is not. The monic polynomial involved is generally of higher degree than those of the original algebraic integers, and can be found by taking resultants and factoring. For example, if x² − x − 1 = 0, y³ − y − 1 = 0 and z = xy, then eliminating x and y from z − xy = 0 and the polynomials satisfied by x and y using the resultant gives z⁶ − 3z⁴ − 4z³ + z² + z − 1 = 0, which is irreducible, and is the monic equation satisfied by the product. (To see that the xy is a root of the x-resultant of z − xy and x² − x − 1, one might use the fact that the resultant is contained in the ideal generated by its two input polynomials.)
• Any number constructible out of the integers with roots, addition, and multiplication is therefore an algebraic integer; but not all algebraic integers are so constructible: in a naïve sense, most roots of irreducible quintics are not. This is the Abel–Ruffini theorem.
• Every root of a monic polynomial whose coefficients are algebraic integers is itself an algebraic integer. In other words, the algebraic integers form a ring which is integrally closed in any of its extensions.
• The ring of algebraic integers is a Bézout domain, as a consequence of the principal ideal theorem.
• If the monic polynomial associated with an algebraic integer has constant term 1 or −1, then the reciprocal of that algebraic integer is also an algebraic integer, and is a unit, an element of the group of units of the ring of algebraic integers.
• Every algebraic number can be written as the ratio of an algebraic integer to a non-zero algebraic integer. In fact, the denominator can always be chosen to be a positive integer. Specifically, if x is an algebraic number that is a root of the polynomial p(x) with integer coefficients and leading term a_nxⁿ for a_n > 0 then a_nx / a_n is the promised ratio. In particular, y = a_nx is an algebraic integer because it is a root of a^n − 1
  _n p(y /a_n), which is a monic polynomial in y with integer coefficients.

• Integral element
• Gaussian integer
• Eisenstein integer
• Root of unity
• Dirichlet's unit theorem
• Fundamental units