Sand Hill (Herkimer County, New York)

Sand Hill is a summit located in Central New York Region of New York located in the Town of Russia in Herkimer County, east-northeast of Poland.

Sand Hill
Sand Hill is located in New York
Sand Hill
Sand Hill
Location of Sand Hill within New York
Sand Hill is located in the United States
Sand Hill
Sand Hill
Sand Hill (the United States)
Highest point
Elevation1,542 feet (470 m)
Coordinates43°15′31″N 75°00′53″W[1]
Geography
LocationENE of Poland, New York, U.S.
Topo mapUSGS Hinckley

References
  1. "Sand Hill". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 2017-12-08.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.