Cantor's diagonal argument

The uncountability of the real numbers was already established by Cantor's first uncountability proof, but it also follows from the above result. To prove this, an injection will be constructed from the set T of infinite binary strings to the set R of real numbers. Since T is uncountable, the image of this function, which is a subset of R, is uncountable. Therefore, R is uncountable. Also, by using a method of construction devised by Cantor, a bijection will be constructed between T and R. Therefore, T and R have the same cardinality, which is called the "cardinality of the continuum" and is usually denoted by ${\displaystyle {\mathfrak {c}}}$ or ${\displaystyle 2^{\aleph _{0}}}$.

An injection from T to R is given by mapping binary strings in T to decimal fractions, such as mapping t = 0111... to the decimal 0.0111.... This function, defined by f (t) = 0.t, is an injection because it maps different strings to different numbers.[note 3]

Constructing a bijection between T and R is slightly more complicated. Instead of mapping 0111... to the decimal 0.0111..., it can be mapped to the base b number: 0.0111..._b. This leads to the family of functions: f_b (t) = 0.t_b. The functions f _b(t) are injections, except for f ₂(t). This function will be modified to produce a bijection between T and R.

Construction of a bijection between T and R

The function h: (0,1) → (−π/2,π/2) The function tan: (−π/2,π/2) → R This construction uses a method devised by Cantor that was published in 1878. He used it to construct a bijection between the closed interval [0, 1] and the irrationals in the open interval (0, 1). He first removed a countably infinite subset from each of these sets so that there is a bijection between the remaining uncountable sets. Since there is a bijection between the countably infinite subsets that have been removed, combining the two bijections produces a bijection between the original sets.[9] Cantor's method can be used to modify the function f 2(t) = 0.t2 to produce a bijection from T to (0, 1). Because some numbers have two binary expansions, f 2(t) is not even injective. For example, f 2(1000...) = 0.1000...2 = 1/2 and f 2(0111...) = 0.0111...2 = 1/4 + 1/8 + 1/16 + ... = 1/2, so both 1000... and 0111... map to the same number, 1/2. To modify f2 (t), observe that it is a bijection except for a countably infinite subset of (0, 1) and a countably infinite subset of T. It is not a bijection for the numbers in (0, 1) that have two binary expansions. These are called dyadic numbers and have the form m / 2n where m is an odd integer and n is a natural number. Put these numbers in the sequence: r = (1/2, 1/4, 3/4, 1/8, 3/8, 5/8, 7/8, ...). Also, f2 (t) is not a bijection to (0, 1) for the strings in T appearing after the binary point in the binary expansions of 0, 1, and the numbers in sequence r. Put these eventually-constant strings in the sequence: s = (000..., 111..., 1000..., 0111..., 01000..., 00111..., 11000..., 10111..., ...). Define the bijection g(t) from T to (0, 1): If t is the nth string in sequence s, let g(t) be the nth number in sequence r ; otherwise, g(t) = 0.t2. To construct a bijection from T to R, start with the tangent function tan(x), which is a bijection from (−π/2, π/2) to R (see the figure shown on the right). Next observe that the linear function h(x) = πx – π/2 is a bijection from (0, 1) to (−π/2, π/2) (see the figure shown on the left). The composite function tan(h(x)) = tan(πx – π/2) is a bijection from (0, 1) to R. Composing this function with g(t) produces the function tan(h(g(t))) = tan(πg(t) – π/2), which is a bijection from T to R.

Illustration of the generalized diagonal argument: The set T = {n∈${\displaystyle \mathbb {N} }$: n∉f(n)} at the bottom cannot occur anywhere in the range of f:${\displaystyle \mathbb {N} }$→P(${\displaystyle \mathbb {N} }$). The example mapping f happens to correspond to the example enumeration s in the above picture.

A generalized form of the diagonal argument was used by Cantor to prove Cantor's theorem: for every set S, the power set of S—that is, the set of all subsets of S (here written as P(S))—cannot be in bijection with S itself. This proof proceeds as follows:

Let f be any function from S to P(S). It suffices to prove f cannot be surjective. That means that some member T of P(S), i.e. some subset of S, is not in the image of f. As a candidate consider the set:

T = { s ∈ S: s ∉ f(s) }.

For every s in S, either s is in T or not. If s is in T, then by definition of T, s is not in f(s), so T is not equal to f(s). On the other hand, if s is not in T, then by definition of T, s is in f(s), so again T is not equal to f(s); cf. picture. For a more complete account of this proof, see Cantor's theorem.

Cantor defines an order relation of cardinalities, e.g. ${\displaystyle |S|}$ and ${\displaystyle |T|}$, in terms of the existence of injections between the underlying sets, ${\displaystyle S}$ and ${\displaystyle T}$. The argument in the previous paragraph then proved that sets such as ${\displaystyle {\mathbb {N} }\to \{0,1\}}$ are uncountable, which is to say ${\displaystyle \neg (|{\mathbb {N} }\to \{0,1\}|\leq |{\mathbb {N} }|)}$, and we can embed the naturals into the function space, so that we have that ${\displaystyle |{\mathbb {N} }|<|{\mathbb {N} }\to \{0,1\}|}$. In the context of classical mathematics, this exhausts the possibilities and the diagonal argument can thus be used to establish that, for example, although both sets under consideration are infinite, there are actually more infinite sequences of ones and zeros than there are natural numbers. Cantor's result then also implies that the notion of the set of all sets is inconsistent: If S were the set of all sets, then P(S) would at the same time be bigger than S and a subset of S.

Assuming the law of excluded middle, every subcountable set (a property in terms of surjections) is also already countable.

In Constructive mathematics, it is harder or impossible to order ordinals and also cardinals. For example, the Schröder–Bernstein theorem requires the law of excluded middle.[10] Therefore, intuitionists do not accept the theorem about the cardinal ordering.[11] The ordering on the reals (the standard ordering extending that of the rational numbers) is also not necessarily decidable. Neither are most properties of interesting classes of functions decidable, by Rice's theorem, i.e. the right set of counting numbers for the subcountable sets may not be recursive. In a set theory, theories of mathematics are modeled. For example, in set theory, "the" set of real numbers is identified as a set that fulfills some axioms of real numbers. Various models have been studied, such as the Dedekind reals or the Cauchy reals. Weaker axioms mean less constraints and so allow for a richer class of models. Consequently, in an otherwise constructive context (law of excluded middle not taken as axiom), it is consistent to adopt non-classical axioms that contradict consequences of the law of excluded middle. For example, the uncountable space of functions ${\displaystyle {\mathbb {N} }\to \{0,1\}}$ may be asserted to be subcountable, a notion of size orthogonal to the statement ${\displaystyle |{\mathbb {N} }|<|{\mathbb {N} }\to \{0,1\}|}$.[12] In such a context, the subcountability of all sets is possible, or injections from the uncountable ${\displaystyle {\mathbb {N} }^{\mathbb {N} }}$ into ${\displaystyle {\mathbb {N} }}$.[13]

Motivated by the insight that the set of real numbers is "bigger" than the set of natural numbers, one is led to ask if there is a set whose cardinality is "between" that of the integers and that of the reals. This question leads to the famous continuum hypothesis. Similarly, the question of whether there exists a set whose cardinality is between |S| and |P(S)| for some infinite S leads to the generalized continuum hypothesis.

Russell's Paradox has shown that naive set theory, based on an unrestricted comprehension scheme, is contradictory. Note that there is a similarity between the construction of T and the set in Russell's paradox. Therefore, depending on how we modify the axiom scheme of comprehension in order to avoid Russell's paradox, arguments such as the non-existence of a set of all sets may or may not remain valid.

Analogues of the diagonal argument are widely used in mathematics to prove the existence or nonexistence of certain objects. For example, the conventional proof of the unsolvability of the halting problem is essentially a diagonal argument. Also, diagonalization was originally used to show the existence of arbitrarily hard complexity classes and played a key role in early attempts to prove P does not equal NP.