Examples of volume in the following topics:
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- Three dimensional mathematical shapes are also assigned volumes.
- A volume integral is a triple integral of the constant function $1$, which gives the volume of the region $D$.
- Using the triple integral given above, the volume is equal to:
- Triple integral of a constant function $1$ over the shaded region gives the volume.
- Calculate the volume of a shape by using the triple integral of the constant function 1
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- Integration, as an accumulative process, can then calculate the integrated volume of a "family" of shells (a shell being the outer edge of a hollow cylinder), giving us the total volume.
- Therefore, the entire integrand, $2\pi x \left | f(x) - g(x) \right | \,dx$, is nothing but the volume of the cylindrical shell.
- By adding the volumes of all these infinitely thin cylinders, we can calculate the volume of the solid formed by the revolution.
- The volume of solid formed by rotating the area between the curves of $f(y)$ and and the lines $y=a$ and $y=b$ about the $x$-axis is given by:
- Calculating volume using the shell method.
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- Disc and shell methods of integration can be used to find the volume of a solid produced by revolution.
- Here, we will study how to compute volumes of these objects.
- Summing up all of the areas along the interval gives the total volume.
- The volume of each infinitesimal disc is therefore:
- Summing up all of the surface areas along the interval gives the total volume.
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- A packaging company needs cardboard boxes in rectangular cuboid shape with a given volume of 1000 cubic centimeters and would like to minimize the material cost for the boxes.
- The constraint in the case is that the volume is fixed: $V = xyz = 1000$.
- That is to say, the box that minimizes the cost of materials while maintaining the desired volume should be a 10-by-10-by-10 cube.
- Mathematical optimization can be used to solve problems that involve finding the right size of a volume such as a cuboid.
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- If the mass distribution is continuous with the density $\rho (r)$ within a volume $V$, then the integral of the weighted position coordinates of the points in this volume relative to the center of mass $\mathbf{R}$ is zero; that is:
- where $M$ is the total mass in the volume.
- The integral is over the three dimensional volume, so it is a triple integral.
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- More precisely, the divergence theorem states that the outward flux of a vector field through a closed surface is equal to the volume integral of the divergence over the region inside the surface.
- Suppose $V$ is a subset of $R^n$ (in the case of $n=3$, $V$ represents a volume in 3D space) which is compact and has a piecewise smooth boundary $S$ (also indicated with $\partial V=S$).
- The left side is a volume integral over the volume $V$; the right side is the surface integral over the boundary of the volume $V$.
- The divergence theorem can be used to calculate a flux through a closed surface that fully encloses a volume, like any of the surfaces on the left.
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- If the mass distribution is continuous with respect to the density, $\rho (r)$, within a volume, $V$, then the integral of the weighted position coordinates of the points in this volume relative to the center of mass, $\mathbf{R}$, is zero, that is:
- where $M$ is the total mass in the volume.
- If a continuous mass distribution has uniform density, which means $\rho$ is constant, then the center of mass is the same as the centroid of the volume.
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- Just as the definite integral of a positive function of one variable represents the area of the region between the graph of the function and the $x$-axis, the double integral of a positive function of two variables represents the volume of the region between the surface defined by the function (on the three dimensional Cartesian plane where $z = f(x, y))$ and the plane which contains its domain.
- The same volume can be obtained via the triple integral—the integral of a function in three variables—of the constant function $f(x, y, z) = 1$ over the above-mentioned region between the surface and the plane.
- Double integral as volume under a surface $z = x^2 − y^2$.
- Use double integrals to find the volume of rectangular regions in the xy-plane
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- In mechanics, the moment of inertia is calculated as the volume integral (triple integral) of the density weighed with the square of the distance from the axis:
- If there is a continuous function $\rho(x)$ representing the density of the distribution at $x$, so that $dm(x) = \rho (x)d^3x$, where $d^3x$ is the Euclidean volume element, then the gravitational potential is:
- In the following example, the electric field produced by a distribution of charges given by the volume charge density $\rho (\vec r)$ is obtained by a triple integral of a vector function:
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- The volume is changing at a rate of 2 cubic feet per minute.
- The relevant formulas and pieces of information are the volume of the balloon, the rate of change of the volume, and the radius.