isotropic
(adjective)
Having properties that are identical in all directions; exhibiting isotropy.
Examples of isotropic in the following topics:
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Emission
- If the emitter is isotropic or the emitters are randomly oriented then the total power emitted per unit volume and unit frequency is
- Often the emission is isotropic and it is convenient to define the emissivity of the material per unit mass
- $\epsilon_\nu$ is simply related to $j_\nu$ for an isotropic emitter
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Flux
- For example, if you have an isotropic source, the flux is constant across a spherical surface centered on the source, so you find that
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Eddington Approximation
- In this region, the radiation field is nearly isotropic, but it need not be close to a blackbody distribution.
- Because the intensity is close to isotropic we can approximate it by
- which we found earlier to hold for strictly isotropic radiation fields.
- The source function $S_\nu$ is isotropic, so let's average the radiative transfer equation over direction to yield
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Volume Expansion
- Such substances that expand in all directions are called isotropic.
- For isotropic materials, the area and linear coefficients may be calculated from the volumetric coefficient (discussed below).
- For isotropic material, and for small expansions, the linear thermal expansion coefficient is one third the volumetric coefficient.
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A Physical Aside: Intensity and Flux
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Inverse Compton Scattering
- If we assume that the photon distribution is isotropic, the angle $\langle \cos\theta \rangle = 0$.
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Dipole Approximation
- The factor of threes arise because we assume that the radiation is isotropic so the value of $E_x^2$ is typically one third of $E^2$ .
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Energy Density
- But let's assume that the radiation field is isotropic, so $I = J$ for all directions, we get
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Inverse Compton Spectra - Single Scattering
- Let's suppose that we have an isotropic distribution of photons of a single energy $E_0$ and a beam of electrons traveling along the $x$-axis with energy $\gamma m c^2$ and density $N$.
- Let's assume that there are many beams isotropically distributed, so we need to find the mean value of $j(E_f,\mu_f)$ over angle,
- To be more precise, we could have relaxed the assumption that the scattering is isotropic and we would have found
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Ionization Equilibrium - the Saha Equation
- Furthermore, if we assume that the electron velocity distribution is isotropic we can derive