1804 United States presidential election in Massachusetts
The 1804 United States presidential election in Massachusetts took place between November 2 and December 5, 1804, as part of the 1804 United States presidential election. Voters chose 17 representatives, or electors to the Electoral College, who voted for president and Vice President.
![]() | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
Elections in Massachusetts |
---|
![]() |
![]() |
During this election, the Federalist Party continued to lose ground as incumbent president Thomas Jefferson won all 17 Massachusetts state electors by a narrow margin of 7.16%. Jefferson would end up as the winner of the 1804 United States presidential election in a landslide victory.
Results
1804 United States presidential election in Massachusetts[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | Thomas Jefferson (incumbent) | 29,599 | 53.58% | 17 | |
Federalist | Charles C. Pinckney | 25,644 | 46.42% | 0 | |
Totals | 55,243 | 100.0% | 17 | ||
1804 Vice Presidential Electoral Vote[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Electoral votes | |||
Democratic-Republican | George Clinton (incumbent) | 17 | |||
Federalist | Rufus King | 0 | |||
Totals | 17 |
See also
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.