1862 Chicago mayoral election

In the Chicago mayoral election of 1862, Democrat Francis Cornwall Sherman won a second non-consecutive term, defeating Republican Party nominee Charles N. Holden.

1862 Chicago mayoral election
April 15, 1862
 
Nominee Francis Cornwall Sherman Charles N. Holden
Party Democratic Republican
Popular vote 7,437 6,254
Percentage 54.32% 45.68%

Mayor before election

Julian Sidney Rumsey
Republican

Elected Mayor

Francis Cornwall Sherman
Democratic

Sherman had previously served as mayor two decades earlier, after winning the 1841 election. He had also been an unsuccessful candidate in the 1856 mayoral election.

Campaign

The election was held on April 15, 1862.[1] It was the second of four Chicago mayoral elections which took place during the course of the American Civil War. It was also last regularly-scheduled Chicago mayoral election to a one-year term.

Democratic nominee Francis Cornwall Sherman, was a businessman who had previously served as mayor from 1841 through 1842.[1][2] He was also supported by a nonpartisan ticket which bore the slogan "for the Union and the Constitution".[2] Due to the fact that his son was a noted brigadier in the Union Army, Sherman was able to comfortably avoid accusations that his own loyalties sided anywhere but with the Union.[2]

Charles N. Holden, a former Chicago alderman and former Chicago City Treasurer, was the nominee of the Republican Party.[2][3] Efforts had been made for the party to nominate former congressman and mayor John Wentworth. However, Holden supporters succeeded in getting him nominated over Wentworth.[2] Some Wentworth supporters, angered over this, placed their support behind Sherman instead.[2]

Results

1862 Chicago mayoral election[4]
Party Candidate Votes %
Democratic Francis Cornwall Sherman 7,437 54.32
Republican Charles N. Holden 6,254 45.68
Turnout 12,508

References


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