1988 Athens Trophy – Singles
Katerina Maleeva was the defending champion but did not compete that year.
Singles | |
---|---|
1988 Athens Trophy | |
Champion | Isabel Cueto |
Runner-up | Laura Golarsa |
Score | 6–0, 6–1 |
Draw | 32 |
Seeds | 8 |
Isabel Cueto won in the final 6–0, 6–1 against Laura Golarsa.
Seeds
A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.
- Isabel Cueto (champion)
- Judith Wiesner (quarterfinals)
- Barbara Paulus (semifinals)
- Sabrina Goleš (second round)
- Angeliki Kanellopoulou (quarterfinals)
- Laura Garrone (first round)
- Silke Meier (first round)
- Laura Golarsa (final)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
References
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.