1991 Indian Challenge

The 1991 Indian Challenge was an invitational non-ranking snooker tournament held in India in 1991. Stephen Hendry won the title, defeating John Parrott 9–5 in the final, and received £20,000 prize money. Parrott compiled the highest break of the tournament, 132, in the semi-final, having made a 127 break in the preceding frame.[1][2]

1991 Indian Challenge
Tournament information
VenueTaj Palace Intercontinental Hotel, Delhi
CountryIndia
FormatNon-ranking event
Winner's share£20,000
Highest break John Parrott (ENG) 132
Final
Champion Stephen Hendry (SCO)
Runner-up John Parrott (ENG)
Score9–5

Results

[1]

First round
Best-of-9 frames 		Quarter-finals
Best-of-9 frames 		Semi-finals
Best-of-9 frames 		Final
Best-of-17 frames
        
 John Parrott (ENG) 5
 Michael Ferreira (IND) 0
England John Parrott 5
England Mike Hallett 2
 Mike Hallett (ENG) 5
 Dennis Taylor (NIR) 2
England John Parrott 5
England Gary Wilkinson 3
 Gary Wilkinson (ENG) 5
 Chuchart Trirattanapradit (THA) 2
England Gary Wilkinson 5
England Jimmy White 2
 Jimmy White (ENG) 5
 Atul Agarwal (IND) 0
England John Parrott 5
Scotland Stephen Hendry 9
 Stephen Hendry (SCO) 5
 Sonic Multani (IND) 4
Scotland Stephen Hendry 5
England Steve James 3
 Steve James (ENG) 5
 Terry Griffiths (WAL) 2
Scotland Stephen Hendry 5
England Steve Davis 3
 Neal Foulds (ENG) 5
 James Wattana (THA) 3
England Neal Foulds 2
England Steve Davis 5
 Steve Davis (ENG) 5
 Geet Sethi (IND) 0

References
  1. "Hendry survives scare and wins again". Snooker Scene. Birmingham: Everton's News Agency. October 1991. p. 23.
  2. Turner, Chris. "Other Non-Ranking and Invition Events". cajt.pwp.blueyonder.co.uk. Chris Turner's Snooker Archive. Archived from the original on 16 February 2012. Retrieved 24 October 2012.
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