2020 Prague Open – Doubles

Anna Kalinskaya and Viktória Kužmová were the defending champions, but chose not to participate.

Doubles
2020 Prague Open
ChampionsCzech Republic Lucie Hradecká
Czech Republic Kristýna Plíšková
Runners-upRomania Monica Niculescu
Romania Raluca Olaru
Score6–2, 6–2

Lucie Hradecká and Kristýna Plíšková won the title, defeating Monica Niculescu and Raluca Olaru in the final, 6–2, 6–2.

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Czech Republic B Krejčíková
Czech Republic K Siniaková
6 3 [10]
Germany A-L Friedsam
Romania LI Paar
4 6 [4] 1 Czech Republic B Krejčíková
Czech Republic K Siniaková
6 77
Romania S Halep
Czech Republic B Strýcová
3 6 [8] Russia V Kudermetova
Russia A Pavlyuchenkova
1 61
Russia V Kudermetova
Russia A Pavlyuchenkova
6 3 [10] 1 Czech Republic B Krejčíková
Czech Republic K Siniaková
64 7 [5]
4 Romania M Niculescu
Romania R Olaru
1 6 [12] 4 Romania M Niculescu
Romania R Olaru
77 5 [10]
Norway U Eikeri
France E Lechemia
6 3 [10] 4 Romania M Niculescu
Romania R Olaru
6 6
Belarus L Marozava
Russia Y Sizikova
w/o Belarus L Marozava
Russia Y Sizikova
2 1
Romania A Bogdan
Romania PM Țig
4 Romania M Niculescu
Romania R Olaru
2 2
WC Czech Republic M Kolodziejová
Czech Republic J Malečková
1 6 [4] 2 Czech Republic L Hradecká
Czech Republic Kr Plíšková
6 6
Netherlands R van der Hoek
Belgium Y Wickmayer
6 1 [10] Netherlands R van der Hoek
Belgium Y Wickmayer
4 2
Netherlands A Rus
Slovenia T Zidanšek
6 6 Netherlands A Rus
Slovenia T Zidanšek
6 6
3 Australia E Perez
Australia S Sanders
3 2 Netherlands A Rus
Slovenia T Zidanšek
3 6 [4]
WC Czech Republic L Fruhvirtová
Czech Republic D Viďmanová
5 2 2 Czech Republic L Hradecká
Czech Republic Kr Plíšková
6 3 [10]
Sweden C Lister
Czech Republic R Voráčová
7 6 Sweden C Lister
Czech Republic R Voráčová
3 4
Germany T Morderger
Germany Y Morderger
1 3 2 Czech Republic L Hradecká
Czech Republic Kr Plíšková
6 6
2 Czech Republic L Hradecká
Czech Republic Kr Plíšková
6 6

References

    This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.