Isomorphism theorems

Below we present four theorems, labelled A, B, C and D. They are often numbered as "First isomorphism theorem", "Second..." and so on; however, there is no universal agreement on the numbering. Here we give some examples of the group isomorphism theorems in the literature. Notice that these theorems have analogs for rings and modules.

It is less common to include the Theorem D, usually known as the lattice theorem or the correspondence theorem, as one of isomorphism theorems, but when included, it is the last one.

Diagram of the fundamental theorem on homomorphisms

Let G and H be groups, and let f : G → H be a homomorphism. Then:

1. The kernel of f is a normal subgroup of G,
2. The image of f is a subgroup of H, and
3. The image of f is isomorphic to the quotient group G / ker(f).

In particular, if f is surjective then H is isomorphic to G / ker(f).

This theorem is usually called the first isomorphism theorem.

Diagram for theorem B4. The two quotient groups (dotted) are isomorphic.

Let ${\displaystyle G}$ be a group. Let ${\displaystyle S}$ be a subgroup of ${\displaystyle G}$, and let ${\displaystyle N}$ be a normal subgroup of ${\displaystyle G}$. Then the following hold:

1. The product ${\displaystyle SN}$ is a subgroup of ${\displaystyle G}$,
2. The subgroup ${\displaystyle N}$ is a normal subgroup of ${\displaystyle SN}$,
3. The intersection ${\displaystyle S\cap N}$ is a normal subgroup of ${\displaystyle S}$, and
4. The quotient groups ${\displaystyle (SN)/N}$ and ${\displaystyle S/(S\cap N)}$ are isomorphic.

Technically, it is not necessary for ${\displaystyle N}$ to be a normal subgroup, as long as ${\displaystyle S}$ is a subgroup of the normalizer of ${\displaystyle N}$ in ${\displaystyle G}$. In this case, ${\displaystyle N}$ is not a normal subgroup of ${\displaystyle G}$, but ${\displaystyle N}$ is still a normal subgroup of the product ${\displaystyle SN}$.

This theorem is sometimes called the second isomorphism theorem,[10] diamond theorem[12] or the parallelogram theorem.[13]

An application of the second isomorphism theorem identifies projective linear groups: for example, the group on the complex projective line starts with setting ${\displaystyle G=\operatorname {GL} _{2}(\mathbb {C} )}$, the group of invertible 2 × 2 complex matrices, ${\displaystyle S=\operatorname {SL} _{2}(\mathbb {C} )}$, the subgroup of determinant 1 matrices, and ${\displaystyle N}$ the normal subgroup of scalar matrices ${\displaystyle \mathbb {C} ^{\times }\!I=\left\{\left({\begin{smallmatrix}a&0\\0&a\end{smallmatrix}}\right):a\in \mathbb {C} ^{\times }\right\}}$, we have ${\displaystyle S\cap N=\{\pm I\}}$, where ${\displaystyle I}$ is the identity matrix, and ${\displaystyle SN=\operatorname {GL} _{2}(\mathbb {C} )}$. Then the second isomorphism theorem states that:

${\displaystyle \operatorname {PGL} _{2}(\mathbb {C} ):=\operatorname {GL} _{2}\left(\mathbb {C} )/(\mathbb {C} ^{\times }\!I\right)\cong \operatorname {SL} _{2}(\mathbb {C} )/\{\pm I\}=:\operatorname {PSL} _{2}(\mathbb {C} )}$

Let ${\displaystyle G}$ be a group, and ${\displaystyle N}$ a normal subgroup of ${\displaystyle G}$. Then

1. If ${\displaystyle K}$ is a subgroup of ${\displaystyle G}$ such that ${\displaystyle N\subseteq K\subseteq G}$, then ${\displaystyle G/N}$ has a subgroup isomorphic to ${\displaystyle K/N}$.
2. Every subgroup of ${\displaystyle G/N}$ is of the form ${\displaystyle K/N}$ for some subgroup ${\displaystyle K}$ of ${\displaystyle G}$ such that ${\displaystyle N\subseteq K\subseteq G}$.
3. If ${\displaystyle K}$ is a normal subgroup of ${\displaystyle G}$ such that ${\displaystyle N\subseteq K\subseteq G}$, then ${\displaystyle G/N}$ has a normal subgroup isomorphic to ${\displaystyle K/N}$.
4. Every normal subgroup of ${\displaystyle G/N}$ is of the form ${\displaystyle K/N}$ for some normal subgroup ${\displaystyle K}$ of ${\displaystyle G}$ such that ${\displaystyle N\subseteq K\subseteq G}$.
5. If ${\displaystyle K}$ is a normal subgroup of ${\displaystyle G}$ such that ${\displaystyle N\subseteq K\subseteq G}$, then the quotient group ${\displaystyle (G/N)/(K/N)}$ is isomorphic to ${\displaystyle G/K}$.

The last statement is sometimes referred to as the third isomorphism theorem. The first four statements are often subsumed under Theorem D below, and referred to as the lattice theorem, correspondence theorem, or fourth isomorphism theorem.

Let ${\displaystyle G}$ be a group, and ${\displaystyle N}$ a normal subgroup of ${\displaystyle G}$. The canonical projection homomorphism ${\displaystyle G\rightarrow G/N}$ defines a bijective correspondence between the set of subgroups of ${\displaystyle G}$ containing ${\displaystyle N}$ and the set of (all) subgroups of ${\displaystyle G/N}$. Under this correspondence normal subgroups correspond to normal subgroups.

This theorem is sometimes called the correspondence theorem, the lattice theorem, and the fourth isomorphism theorem.

The Zassenhaus lemma (also known as the butterfly lemma) is sometimes called the fourth isomorphism theorem.[14]

The first isomorphism theorem can be expressed in category theoretical language by saying that the category of groups is (normal epi, mono)-factorizable; in other words, the normal epimorphisms and the monomorphisms form a factorization system for the category. This is captured in the commutative diagram in the margin, which shows the objects and morphisms whose existence can be deduced from the morphism ${\displaystyle f:G\rightarrow H}$. The diagram shows that every morphism in the category of groups has a kernel in the category theoretical sense; the arbitrary morphism f factors into ${\displaystyle \iota \circ \pi }$, where ι is a monomorphism and π is an epimorphism (in a conormal category, all epimorphisms are normal). This is represented in the diagram by an object ${\displaystyle \ker f}$ and a monomorphism ${\displaystyle \kappa$ :\ker f\rightarrow G} (kernels are always monomorphisms), which complete the short exact sequence running from the lower left to the upper right of the diagram. The use of the exact sequence convention saves us from having to draw the zero morphisms from ${\displaystyle \ker f}$ to ${\displaystyle H}$ and ${\displaystyle G/\ker f}$.

If the sequence is right split (i.e., there is a morphism σ that maps ${\displaystyle G/\operatorname {ker} f}$ to a π-preimage of itself), then G is the semidirect product of the normal subgroup ${\displaystyle \operatorname {im} \kappa }$ and the subgroup ${\displaystyle \operatorname {im} \sigma }$. If it is left split (i.e., there exists some ${\displaystyle \rho :G\rightarrow \operatorname {ker} f}$ such that ${\displaystyle \rho \circ \kappa =\operatorname {id} _{{\text{ker}}f}}$), then it must also be right split, and ${\displaystyle \operatorname {im} \kappa \times \operatorname {im} \sigma }$ is a direct product decomposition of G. In general, the existence of a right split does not imply the existence of a left split; but in an abelian category (such as that of abelian groups), left splits and right splits are equivalent by the splitting lemma, and a right split is sufficient to produce a direct sum decomposition ${\displaystyle \operatorname {im} \kappa \oplus \operatorname {im} \sigma }$. In an abelian category, all monomorphisms are also normal, and the diagram may be extended by a second short exact sequence ${\displaystyle 0\rightarrow G/\operatorname {ker} f\rightarrow H\rightarrow \operatorname {coker} f\rightarrow 0}$.

In the second isomorphism theorem, the product SN is the join of S and N in the lattice of subgroups of G, while the intersection S ∩ N is the meet.

The third isomorphism theorem is generalized by the nine lemma to abelian categories and more general maps between objects.

Let ${\displaystyle R}$ and ${\displaystyle S}$ be rings, and let ${\displaystyle \varphi :R\rightarrow S}$ be a ring homomorphism. Then:

1. The kernel of ${\displaystyle \varphi }$ is an ideal of ${\displaystyle R}$,
2. The image of ${\displaystyle \varphi }$ is a subring of ${\displaystyle S}$, and
3. The image of ${\displaystyle \varphi }$ is isomorphic to the quotient ring ${\displaystyle R/\ker \varphi }$.

In particular, if ${\displaystyle \varphi }$ is surjective then ${\displaystyle S}$ is isomorphic to ${\displaystyle R/\ker \varphi }$.[15]

Let R be a ring. Let S be a subring of R, and let I be an ideal of R. Then:

1. The sum S + I = {s + i | s ∈ S, i ∈ I } is a subring of R,
2. The intersection S ∩ I is an ideal of S, and
3. The quotient rings (S + I) / I and S / (S ∩ I) are isomorphic.

Let R be a ring, and I an ideal of R. Then

1. If ${\displaystyle A}$ is a subring of ${\displaystyle R}$ such that ${\displaystyle I\subseteq A\subseteq R}$, then ${\displaystyle A/I}$ is a subring of ${\displaystyle R/I}$.
2. Every subring of ${\displaystyle R/I}$ is of the form ${\displaystyle A/I}$ for some subring ${\displaystyle A}$ of ${\displaystyle R}$ such that ${\displaystyle I\subseteq A\subseteq R}$.
3. If ${\displaystyle J}$ is an ideal of ${\displaystyle R}$ such that ${\displaystyle I\subseteq J\subseteq R}$, then ${\displaystyle J/I}$ is an ideal of ${\displaystyle R/I}$.
4. Every ideal of ${\displaystyle R/I}$ is of the form ${\displaystyle J/I}$ for some ideal ${\displaystyle J}$ of ${\displaystyle R}$ such that ${\displaystyle I\subseteq J\subseteq R}$.
5. If ${\displaystyle J}$ is an ideal of ${\displaystyle R}$ such that ${\displaystyle I\subseteq J\subseteq R}$, then the quotient ring ${\displaystyle (R/I)/(J/I)}$ is isomorphic to ${\displaystyle R/J}$.

Let ${\displaystyle I}$ be an ideal of ${\displaystyle R}$. The correspondence ${\displaystyle A\leftrightarrow A/I}$ is an inclusion-preserving bijection between the set of subrings ${\displaystyle A}$ of ${\displaystyle R}$ that contain ${\displaystyle I}$ and the set of subrings of ${\displaystyle R/I}$. Furthermore, ${\displaystyle A}$ (a subring containing ${\displaystyle I}$) is an ideal of ${\displaystyle R}$ if and only if ${\displaystyle A/I}$ is an ideal of ${\displaystyle R/I}$.[16]

Let M and N be modules, and let φ : M → N be a module homomorphism. Then:

1. The kernel of φ is a submodule of M,
2. The image of φ is a submodule of N, and
3. The image of φ is isomorphic to the quotient module M / ker(φ).

In particular, if φ is surjective then N is isomorphic to M / ker(φ).

Let M be a module, and let S and T be submodules of M. Then:

1. The sum S + T = {s + t | s ∈ S, t ∈ T} is a submodule of M,
2. The intersection S ∩ T is a submodule of M, and
3. The quotient modules (S + T) / T and S / (S ∩ T) are isomorphic.

Let M be a module, T a submodule of M.

1. If ${\displaystyle S}$ is a submodule of ${\displaystyle M}$ such that ${\displaystyle T\subseteq S\subseteq M}$, then ${\displaystyle S/T}$ is a submodule of ${\displaystyle M/T}$.
2. Every submodule of ${\displaystyle M/T}$ is of the form ${\displaystyle S/T}$ for some submodule ${\displaystyle S}$ of ${\displaystyle M}$ such that ${\displaystyle T\subseteq S\subseteq M}$.
3. If ${\displaystyle S}$ is a submodule of ${\displaystyle M}$ such that ${\displaystyle T\subseteq S\subseteq M}$, then the quotient module ${\displaystyle (M/T)/(S/T)}$ is isomorphic to ${\displaystyle M/S}$.

Let ${\displaystyle M}$ be a module, ${\displaystyle N}$ a submodule of ${\displaystyle M}$. There is a bijection between the submodules of ${\displaystyle M}$ that contain ${\displaystyle N}$ and the submodules of ${\displaystyle M/N}$. The correspondence is given by ${\displaystyle A\leftrightarrow A/N}$ for all ${\displaystyle A\supseteq N}$. This correspondence commutes with the processes of taking sums and intersections (i.e., is a lattice isomorphism between the lattice of submodules of ${\displaystyle M/N}$ and the lattice of submodules of ${\displaystyle M}$ that contain ${\displaystyle N}$).[17]

Let ${\displaystyle f:A\rightarrow B}$ be an algebra homomorphism. Then the image of ${\displaystyle f}$ is a subalgebra of ${\displaystyle B}$, the relation given by ${\displaystyle \Phi :f(x)=f(y)}$ (i.e. the kernel of ${\displaystyle f}$) is a congruence on ${\displaystyle A}$, and the algebras ${\displaystyle A/\Phi }$ and ${\displaystyle \operatorname {im} f}$ are isomorphic. (Note that in the case of a group, ${\displaystyle f(x)=f(y)}$ iff ${\displaystyle f(xy^{-1})=1}$, so one recovers the notion of kernel used in group theory in this case.)

Given an algebra ${\displaystyle A}$, a subalgebra ${\displaystyle B}$ of ${\displaystyle A}$, and a congruence ${\displaystyle \Phi }$ on ${\displaystyle A}$, let ${\displaystyle \Phi _{B}=\Phi \cap (B\times B)}$ be the trace of ${\displaystyle \Phi }$ in ${\displaystyle B}$ and ${\displaystyle [B]^{\Phi }=\{K\in A/\Phi :K\cap B\neq \emptyset \}}$ the collection of equivalence classes that intersect ${\displaystyle B}$. Then

1. ${\displaystyle \Phi _{B}}$ is a congruence on ${\displaystyle B}$,
2. ${\displaystyle \ [B]^{\Phi }}$ is a subalgebra of ${\displaystyle A/\Phi }$, and
3. the algebra ${\displaystyle [B]^{\Phi }}$ is isomorphic to the algebra ${\displaystyle B/\Phi _{B}}$.

Let ${\displaystyle A}$ be an algebra and ${\displaystyle \Phi ,\Psi }$ two congruence relations on ${\displaystyle A}$ such that ${\displaystyle \Psi \subseteq \Phi }$. Then ${\displaystyle \Phi /\Psi =\{([a']_{\Psi },[a'']_{\Psi }):(a',a'')\in \Phi \}=[\ ]_{\Psi }\circ \Phi \circ [\ ]_{\Psi }^{-1}}$ is a congruence on ${\displaystyle A/\Psi }$, and ${\displaystyle A/\Phi }$ is isomorphic to ${\displaystyle (A/\Psi )/(\Phi /\Psi ).}$

Let ${\displaystyle A}$ be an algebra and denote ${\displaystyle \operatorname {Con} A}$ the set of all congruences on ${\displaystyle A}$. The set ${\displaystyle \operatorname {Con} A}$ is a complete lattice ordered by inclusion.[18] If ${\displaystyle \Phi \in \operatorname {Con} A}$ is a congruence and we denote by ${\displaystyle \left[\Phi ,A\times A\right]\subseteq \operatorname {Con} A}$ the set of all congruences that contain ${\displaystyle \Phi }$ (i.e. ${\displaystyle \left[\Phi ,A\times A\right]}$ is a principal filter in ${\displaystyle \operatorname {Con} A}$, moreover it is a sublattice), then the map ${\displaystyle \alpha$ :\left[\Phi ,A\times A\right]\to \operatorname {Con} (A/\Phi ),\Psi \mapsto \Psi /\Phi } is a lattice isomorphism.[19][20]