1796 Pennsylvania gubernatorial election

1796 Pennsylvania gubernatorial election
	October 11, 1796[1]
	County Results ; Mifflin: 70-80% 80-90% 90-100%
Governor before election; Thomas Mifflin; Democratic-Republican	Elected Governor ; Thomas Mifflin; Democratic-Republican

The 1796 Pennsylvania gubernatorial election occurred on October 11, 1796. Incumbent Democratic-Republican governor Thomas Mifflin successfully sought re-election to a third term. For the second consecutive election, he was victorious over U.S. Representative Frederick Muhlenberg, the Federalist candidate, by a wide margin.

Results

Pennsylvania gubernatorial election, 1796[2][3]
Party		Candidate	Votes	%
	Democratic-Republican	Thomas Mifflin (incumbent)	30,020	96.31
	Federalist	Frederick Muhlenberg	1,011	3.24
	Federalist	Anthony Wayne	139	0.45
Total votes			31,170	100.00

References

"Public Notice is Hereby Given". Gazette of the United States, and Philadelphia daily advertiser. Philadelphia, Pa. October 8, 1796. p. 1. Retrieved December 12, 2022.
"PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.
"Pennsylvania Gubernatorial Election Returns 1796". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.

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[1] "Public Notice is Hereby Given". Gazette of the United States, and Philadelphia daily advertiser. Philadelphia, Pa. October 8, 1796. p. 1. Retrieved December 12, 2022.

[2] "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.

[results2-3] "Pennsylvania Gubernatorial Election Returns 1796". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.