1819 Delaware gubernatorial election
The 1819 Delaware gubernatorial election was held on October 5, 1819. Incumbent Federalist Governor John Clark was unable to seek re-election due to term limits. State Senator Henry Molleston ran as Clark's successor, winning the Federalist nomination. He faced Manaen Bull, Clark's 1816 opponent, and the Democratic-Republican nominee. Molleston won by a fairly wide margin, but died on November 11, 1819, prior to assuming office. State Senate President Jacob Stout became Governor and a special election was held in 1820.[1]
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| Elections in Delaware |
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General election
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Federalist | Henry Molleston | 3,823 | 54.55% | +1.29% | |
| Democratic-Republican | Manaen Bull | 3,185 | 45.45% | -1.29% | |
| Majority | 638 | 9.10% | +2.58% | ||
| Turnout | 7,008 | 100.00% | |||
| Federalist hold | |||||
References
- Conrad, Henry C. (1908). History of the State of Delaware: From the Earliest Settlements to the Year 1907. Vol. 1. Lancaster, Pa.: Wickersham Company, Printers and Binders. p. 176.
- "Delaware 1819 Governor". A New Nation Votes: American Election Returns 1787-1825. Tufts University. Retrieved June 17, 2021.
Bibliography
- Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
- Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
- Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.
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