1910 Vermont gubernatorial election

The 1910 Vermont gubernatorial election took place on September 6, 1910. Incumbent Republican George H. Prouty, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate John A. Mead defeated Democratic candidate Charles D. Watson to succeed him.

1910 Vermont gubernatorial election

September 6, 1910 (1910-09-06)
 
Nominee John A. Mead Charles D. Watson
Party Republican Democratic
Popular vote 35,263 17,425
Percentage 64.2% 31.7%

Governor before election

George H. Prouty
Republican

Elected Governor

John A. Mead
Republican

Marshall J. Hapgood spent $103.76 (equivalent to $3,259 in 2022) during the campaign.[2]

Results

1910 Vermont gubernatorial election[3]
Party Candidate Votes % ±%
Republican John A. Mead 35,263 64.2
Democratic Charles D. Watson 17,425 31.7
Prohibition Edwin R. Towle 1,044 1.9
Socialist Chester E. Ordway 1,055 1.9
N/A Other 141 0.3
Total votes '54,928' '100'

References

  1. Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 1, 2015.
  2. "Politics and Power Forever Linked With Money". Rutland Herald. September 18, 1994. p. 47. Archived from the original on December 9, 2022 via Newspapers.com.
  3. "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on November 30, 2014. Retrieved January 1, 2015.


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