1916 Vermont gubernatorial election

The 1916 Vermont gubernatorial election took place on November 7, 1916. Incumbent Republican Charles W. Gates, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Horace F. Graham defeated Democratic candidate William B. Mayo to succeed him.

1916 Vermont gubernatorial election

November 7, 1916 (1916-11-07)
 
Nominee Horace F. Graham William B. Mayo
Party Republican Democratic
Popular vote 43,265 15,789
Percentage 71.1% 25.9%

County results
Graham:      60–70%      70–80%      80–90%

Governor before election

Charles W. Gates
Republican

Elected Governor

Horace F. Graham
Republican

Republican primary

Results

Republican primary results[2]
Party Candidate Votes % ±%
Republican Horace F. Graham 33,244 99.9
Republican Other 37 0.1
Total votes '33,281' '100'

Democratic primary

Results

Democratic primary results[2]
Party Candidate Votes % ±%
Democratic William B. Mayo 3,562 99.9
Democratic Other 1 0.0
Total votes '3,563' '100'

General election

Results

1916 Vermont gubernatorial election[3]
Party Candidate Votes % ±%
Republican Horace F. Graham 43,265 71.1
Democratic William B. Mayo 15,789 25.9
Socialist W. R. Rowland 920 1.5
Prohibition Lester W. Hanson 876 1.4
N/A Other 4 0.0
Total votes '60,854' '100'

References

  1. Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 1, 2015.
  2. "Primary Election Results" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on January 1, 2015. Retrieved January 1, 2015.
  3. "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on November 30, 2014. Retrieved January 1, 2015.


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