1917 Dutch general election
General elections were held in the Netherlands on 5 and 15 June 1917 to elect members of the House of Representatives of the Dutch Parliament. The elections were held following an agreement between the seven political parties with seats in parliament to allow a change in the constitution to introduce universal male suffrage and proportional representation. Polling was held for 50 constituencies with only one candidate on 5 June, in which 50 MPs were elected. In the other 50 constituencies with opposition candidates, voting was held on 15 July. A second round was required in Amsterdam, where Social Democratic Workers' Party candidate Adriaan Gerhard was re-elected.
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All 100 seats in the House of Representatives 51 seats needed for a majority | |||||||||||||||||||||||||||||||||||||||||||||
Turnout | 21.36% | ||||||||||||||||||||||||||||||||||||||||||||
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Part of the Politics series |
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1,078,205 citizens were eligible to vote of which 230,310 cast a vote, representing a turnout of 21.36%.[1]
Results
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Party | Votes | % | Seats | +/– | |
General League of Roman Catholic Caucuses | 24 | –1 | |||
Liberal Union | 21 | –1 | |||
Social Democratic Workers' Party | 15 | 0 | |||
Anti-Revolutionary Party | 12 | +1 | |||
League of Free Liberals | 10 | 0 | |||
Christian Historical Union | 9 | –1 | |||
Free-thinking Democratic League | 8 | +1 | |||
Other parties | 1 | – | |||
Total | 100 | 0 | |||
Total votes | 230,310 | – | |||
Registered voters/turnout | 1,078,205 | 21.36 |
References
- "Tweede Kamer 15 juni 1917". Kiesraad (in Dutch).