Seward Township, Kosciusko County, Indiana

Seward Township is one of seventeen townships in Kosciusko County, Indiana, United States. As of the 2010 census, its population was 2,567 and it contained 1,385 housing units.[3]

Seward Township
Township
Coordinates: 41°06′29″N 85°56′46″W
CountryUnited States
StateIndiana
CountyKosciusko
Government
 • TypeIndiana township
Area
 • Total36.27 sq mi (93.9 km2)
 • Land34.98 sq mi (90.6 km2)
 • Water1.3 sq mi (3 km2)
Elevation
[1]
876 ft (267 m)
Population
 (2010)
 • Total2,567
 • Density73.4/sq mi (28.3/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
FIPS code18-68796[2]
GNIS feature ID453840

Seward Township was organized in 1859.[4]

Geography

According to the 2010 census, the township has a total area of 36.27 square miles (93.9 km2), of which 34.98 square miles (90.6 km2) (or 96.44%) is land and 1.3 square miles (3.4 km2) (or 3.58%) is water.[3]

Cities and towns

References
  1. "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
  2. "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  3. "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.
  4. Biographical and Historical Record of Kosciusko County, Indiana. Lewis Publishing Company. 1887. p. 728.


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