1806 Virginia gubernatorial election

The 1806 Virginia gubernatorial election was held on 30 November 1806 in order to elect the Governor of Virginia. Incumbent Democratic-Republican Governor of Virginia William H. Cabell won re-election in the Virginia General Assembly as he ran unopposed.[1][2][3]

1806 Virginia gubernatorial election

30 November 1806
 
Nominee William H. Cabell
Party Democratic-Republican
Popular vote 1
Percentage 100.00%

Governor before election

William H. Cabell
Democratic-Republican

Elected Governor

William H. Cabell
Democratic-Republican

General election

On election day, 30 November 1806, Democratic-Republican nominee William H. Cabell easily won re-election as he ran unopposed. Cabell was sworn in for his second term on 1 December 1806.[4][5]

Results

Virginia gubernatorial election, 1806[6][7]
Party Candidate Votes %
Democratic-Republican William H. Cabell (incumbent) 1 100.00
Total votes 1 100.00
Democratic-Republican hold

References

  1. "Gov. William Henry Cabell". nga.org. January 13, 2018. Retrieved May 19, 2023.
  2. "General Assembly of Virginia". The enquirer. Richmond, VA. December 5, 1806. p. 2. Retrieved May 19, 2023.
  3. "Washington City. Wednesday, December 10". The national intelligencer and Washington advertiser. Washington, D.C. December 10, 1806. p. 3. Retrieved May 19, 2023.
  4. "VA Governor". ourcampaigns.com. February 10, 2013. Retrieved May 19, 2023.
  5. "Virginia Legislature. House of Delegates. Wednesday, December 3, 1806". Virginia Argus. Richmond, VA. December 5, 1806. p. 2. Retrieved May 19, 2023.
  6. Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
  7. "Virginia 1806 Governor". elections.lib.tufts.edu. December 5, 1806. Retrieved May 19, 2023.
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