1806 Virginia gubernatorial election
The 1806 Virginia gubernatorial election was held on 30 November 1806 in order to elect the Governor of Virginia. Incumbent Democratic-Republican Governor of Virginia William H. Cabell won re-election in the Virginia General Assembly as he ran unopposed.[1][2][3]
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Elections in Virginia |
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General election
On election day, 30 November 1806, Democratic-Republican nominee William H. Cabell easily won re-election as he ran unopposed. Cabell was sworn in for his second term on 1 December 1806.[4][5]
Results
Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic-Republican | William H. Cabell (incumbent) | 1 | 100.00 | |
Total votes | 1 | 100.00 | ||
Democratic-Republican hold | ||||
References
- "Gov. William Henry Cabell". nga.org. January 13, 2018. Retrieved May 19, 2023.
- "General Assembly of Virginia". The enquirer. Richmond, VA. December 5, 1806. p. 2. Retrieved May 19, 2023.
- "Washington City. Wednesday, December 10". The national intelligencer and Washington advertiser. Washington, D.C. December 10, 1806. p. 3. Retrieved May 19, 2023.
- "VA Governor". ourcampaigns.com. February 10, 2013. Retrieved May 19, 2023.
- "Virginia Legislature. House of Delegates. Wednesday, December 3, 1806". Virginia Argus. Richmond, VA. December 5, 1806. p. 2. Retrieved May 19, 2023.
- Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
- "Virginia 1806 Governor". elections.lib.tufts.edu. December 5, 1806. Retrieved May 19, 2023.
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