First inauguration of Grover Cleveland
The first inauguration of Grover Cleveland as the 22nd president of the United States took place on Wednesday, March 4, 1885, at the East Portico of the United States Capitol in Washington, D.C. This was the 25th inauguration and marked the commencement of the first four-year term of Grover Cleveland as president and the only term of Thomas A. Hendricks as vice president. Hendricks died 266 days into this term, and the office remained vacant since there was no constitutional provision which allow an intra-term vice-presidential office filling; it would be regulated by the Twenty-fifth Amendment in 1967.
Date | March 4, 1885 |
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Location | United States Capitol, Washington, D.C. |
Participants | Grover Cleveland 22nd president of the United States — Assuming office Morrison Waite Chief Justice of the United States — Administering oath Thomas A. Hendricks 21st vice president of the United States — Assuming office George F. Edmunds President pro tempore of the United States Senate — Administering oath |
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28th Governor of New York
22nd & 24th President of the United States
First term
Second term
Presidential campaigns
Post-presidency
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Chief Justice Morrison Waite administered the presidential oath of office, and Cleveland held a Bible given to him at age 15 by his mother as he recited it.[1] Cleveland's second inauguration took place eight years after the first, as his two terms in office were not consecutive. He is the only U.S. president to serve non-consecutive terms.[2]
See also
References
- "The 25th Presidential Inauguration: Grover Cleveland, March 04, 1885". United States Senate. Retrieved May 3, 2020.
- "The 27th Presidential Inauguration, Grover Cleveland, March 04, 1893". United States Senate. Retrieved May 3, 2020.