1822 Rhode Island gubernatorial election

The 1822 Rhode Island gubernatorial election was an uncontested election held on April 17, 1822 to elect the Governor of Rhode Island. William C. Gibbs, the Democratic-Republican nominee, was the only candidate and so won with 100% of the vote.

1822 Rhode Island gubernatorial election

April 17, 1822[1]
 
Nominee William C. Gibbs
Party Democratic-Republican
Popular vote 2,092
Percentage 100%


Governor before election

William C. Gibbs
Democratic-Republican

Elected Governor

William C. Gibbs
Democratic-Republican

General election

Candidates

  • William C. Gibbs, Governor since 1821.[2]

Results

1822 Rhode Island gubernatorial election[3][4]
Party Candidate Votes % ±%
Democratic-Republican William C. Gibbs (incumbent) 2,092 100%
Majority 2,092 100%
Democratic-Republican hold Swing

County results

County results
County[3] William Gibbs

Democratic-Republican

Total votes
# %
Bristol 141 100% 141
Kent 349 100% 349
Newport 514 100% 514
Providence 755 100% 755
Washington 333 100% 333
Totals 2,092 100% 2,092

References

  1. "Election". The Rhode-Island Republican. Newport, R.I. April 24, 1822. p. 2. Retrieved October 24, 2021.
  2. "Governor William Channing Gibbs". National Governor's Association. Archived from the original on March 5, 2017.
  3. "Rhode Island 1822 Governor". A New Nation Votes: American Election Returns 1787-1825. January 11, 2012. Retrieved June 2, 2022.
  4. Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. p. 232. ISBN 9780786414390.


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