1822 Rhode Island gubernatorial election
The 1822 Rhode Island gubernatorial election was an uncontested election held on April 17, 1822 to elect the Governor of Rhode Island. William C. Gibbs, the Democratic-Republican nominee, was the only candidate and so won with 100% of the vote.
| |||||||||||||||||
| |||||||||||||||||
|
General election
Elections in Rhode Island |
---|
Candidates
- William C. Gibbs, Governor since 1821.[2]
Results
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Democratic-Republican | William C. Gibbs (incumbent) | 2,092 | 100% | ||
Majority | 2,092 | 100% | |||
Democratic-Republican hold | Swing | ||||
County results
County[3] | William Gibbs
Democratic-Republican |
Total votes | |
---|---|---|---|
# | % | ||
Bristol | 141 | 100% | 141 |
Kent | 349 | 100% | 349 |
Newport | 514 | 100% | 514 |
Providence | 755 | 100% | 755 |
Washington | 333 | 100% | 333 |
Totals | 2,092 | 100% | 2,092 |
References
- "Election". The Rhode-Island Republican. Newport, R.I. April 24, 1822. p. 2. Retrieved October 24, 2021.
- "Governor William Channing Gibbs". National Governor's Association. Archived from the original on March 5, 2017.
- "Rhode Island 1822 Governor". A New Nation Votes: American Election Returns 1787-1825. January 11, 2012. Retrieved June 2, 2022.
- Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. p. 232. ISBN 9780786414390.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.