1930 Rhode Island gubernatorial election

The 1930 Rhode Island gubernatorial election was held on November 4, 1930. Incumbent Republican Norman S. Case defeated Democratic nominee Theodore F. Green with 50.53% of the vote.

1930 Rhode Island gubernatorial election

November 4, 1930
 
Nominee Norman S. Case Theodore F. Green
Party Republican Democratic
Popular vote 112,070 108,558
Percentage 50.53% 48.95%

Governor before election

Norman S. Case
Republican

Elected Governor

Norman S. Case
Republican

General election

Candidates

Major party candidates

  • Norman S. Case, Republican
  • Theodore F. Green, Democratic

Other candidates

  • Charles H. Dana, Socialist

Results

1930 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Norman S. Case (incumbent) 112,070 50.53%
Democratic Theodore F. Green 108,558 48.95%
Socialist Charles H. Dana 1,168 0.53%
Majority 3,512
Turnout
Republican hold Swing

References

  1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved May 7, 2020.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.