1881 Rhode Island gubernatorial election

The 1881 Rhode Island gubernatorial election was held on April 6, 1881. Incumbent Republican Alfred H. Littlefield defeated Democratic nominee Horace A. Kimball with 66.97% of the vote.

1881 Rhode Island gubernatorial election

April 6, 1881
 
Nominee Alfred H. Littlefield Horace A. Kimball
Party Republican Democratic
Popular vote 10,849 4,756
Percentage 66.97% 29.36%

Governor before election

Alfred H. Littlefield
Republican

Elected Governor

Alfred H. Littlefield
Republican

General election

Candidates

Major party candidates

  • Alfred H. Littlefield, Republican
  • Horace A. Kimball, Democratic

Other candidates

  • Charles P. Adams, Greenback
  • Frank G. Allen, Prohibition

Results

1881 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Alfred H. Littlefield (incumbent) 10,849 66.97%
Democratic Horace A. Kimball 4,756 29.36%
Greenback Charles P. Adams 285 1.76%
Prohibition Frank G. Allen 253 1.56%
Majority 6,093
Turnout
Republican hold Swing

References

  1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved October 20, 2020.
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