1895 Rhode Island gubernatorial election

1895 Rhode Island gubernatorial election
	April 3, 1895
Governor before election; Daniel Russell Brown; Republican	Elected Governor ; Charles W. Lippitt; Republican

The 1895 Rhode Island gubernatorial election was held on April 3, 1895. Republican nominee Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.89% of the vote.

General election

Candidates

Major party candidates

Charles W. Lippitt, Republican
George L. Littlefield, Democratic

Other candidates

Smith Quimby, Prohibition
George Boomer, Socialist Labor
William Foster Jr., People's

Results

1895 Rhode Island gubernatorial election[1]
Party		Candidate	Votes	%
	Republican	Charles W. Lippitt	25,098	56.89%
	Democratic	George L. Littlefield	14,289	32.39%
	Prohibition	Smith Quimby	2,624	5.95%
	Socialist Labor	George Boomer	1,730	3.92%
	Populist	William Foster Jr.	379	0.86%
Majority			10,809
Turnout
	Republican hold		Swing

References

Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 18, 2020.

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[1] Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 18, 2020.