1996 United States presidential election in Rhode Island

1996 United States presidential election in Rhode Island
	November 5, 1996
Turnout	64.8%[1] 11.8 pp
Clinton 40–50% 50–60% 60–70% 70–80%	Dole 40–50%
President before election; Bill Clinton; Democratic	Elected President ; Bill Clinton; Democratic

The 1996 United States presidential election in Rhode Island took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 59.71% to 26.82% by a margin of 32.89%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 11.20% of the popular vote.[2]

As of 2020, this was the most recent presidential election in which the town of Scituate voted for a Democrat.

Results

1996 United States presidential election in Rhode Island
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton (incumbent)	Al Gore	233,050	59.71%	4
	Republican	Bob Dole	Jack Kemp	104,683	26.82%	0
	Reform	Ross Perot	Patrick Choate	43,723	11.20%	0
	Green	Ralph Nader	Winona LaDuke	6,040	1.55%	0
	Libertarian	Harry Browne	Jo Jorgensen	1,109	0.28%	0
	U.S. Taxpayers' Party	Howard Phillips	Herbert Titus	1,021	0.26%	0
	Natural Law	Dr. John Hagelin	Dr. V. Tompkins	435	0.11%	0
	Workers World Party	Monica Moorehead	Gloria La Riva	186	0.05%	0
	No party	Write-in		37	0.01%	0

County	William Jeferson Clinton Democratic		Robert Joseph Dole Republican		Henry Ross Perot Reform		Various candidates Others parties		Total Votes
Name	#	%	#	%	#	%	#	%	#
Providence	134,866	63.6%	49,901	23.5%	22,724	10.7%	4,631	2.2%	212,122
Kent	41,018	57.3%	19,992	28.0%	9,240	12.9%	1,276	1.8%	71,526
Bristol	12,257	56.6%	6,988	32.2%	1,990	9.2%	436	2.0%	21,671
Newport	18,951	54.0%	11,500	32.8%	3,785	10.8%	860	2.5%	35,096
Washington	25,598	51.8%	16,302	33.0%	5,984	12.0%	1,588	3.3%	49,462

This figure is calculated by dividing the total number of votes cast in 1996 (390,247) by an estimate of the number of registered voters in Rhode Island in 1996 (602,692). See "Voter Turnout, 1996". Rhode Island Board of Elections. Retrieved February 6, 2018.
"Dave Leip's Atlas of U.S. Presidential Elections".

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