How to Interpolate

Last Updated: December 19, 2019 References

Linear interpolation, also called simply interpolation or “lerping,”^{[1]
X
Research source} is the ability to deduce a value between two values explicitly stated in a table or on a line graph. While many people can interpolate on an intuitive basis, the article below shows the formalized mathematical approach behind the intuition.

Steps

1
Identify the value for which you want to find a corresponding value. Interpolation can be used for such things as finding a logarithm or trigonometric function value or for the corresponding gas pressure or volume for a given temperature in chemistry.^{[2]
X
Research source} Because scientific calculators have largely replaced logarithmic and trigonometric tables, we’ll use as our example for finding an interpolated value that of finding the pressure of a gas for a temperature whose value isn’t listed in the reference table or as a graph point.
- For the equation we’ll derive, we’ll represent the value that we want to find a corresponding value for as ‘’x’’ and the interpolated value we want to find as ‘’y’’. (We’ll use these labels, because on a graph, the value we know would be plotted on the horizontal, or x-axis, and the value we’re trying to find would be plotted on the vertical, or y-axis.)
- Our ‘’x’’ value will be the temperature of the gas, which for this example will be 37 °C (99 °F).
2
Find the closest values below and above the value of x in the table or on the graph. Our reference table doesn’t give a gas pressure for 37 °C (99 °F), but it does list values for 30 °C (86 °F) and 40 °C (104 °F). The gas pressure at 30 °C (86 °F) is 3 kilopascals (kPa) and the pressure at 40 °C (104 °F) is 5 kPa.
- Because we’re representing the temperature of 37 °C (99 °F) with ‘’x’’, we’ll represent the temperature of 30 degrees as ‘’x₁’’ and the value of 40 degrees as ‘’x₂’’.
- Because we’re representing the pressure were trying to find with ‘’y’’, we’ll represent the pressure of 3 kPa at 30 °C (86 °F) as ‘’y₁’’ and the pressure of 5 kPa at 40 °C (104 °F) as ‘’y₂’’.
Advertisement
3
Find the interpolated value mathematically. The equation for finding the interpolated value can be written as y = y₁ + ((x – x₁)/(x₂ - x₁) * (y₂ - y₁))^{[3]
X
Research source}
- Plugging in the values for x, x₁, and x_/2 in their places gives (37 – 30)/(40 -30), which reduces to 7/10 or 0.7.
- Plugging in the values for y₁ and y₂ at the end of the equation gives (5 – 3) or 2.
- Multiplying 0.7 by 2 gives a product of 1.4. Adding 1.4 to the value of y₁, or 3, gives a value of 4.4 kPa. Checking this against our original values, 4.4 falls between 3 kPa at 30 °C (86 °F) and 5 kPa at 40 °C (104 °F), and because 37 is closer to 40 than it is to 30, the result should be closer to 5 kPa than it is to 3 kPa.

Community Q&A

Question

What is the interpolation of 27.5?

Hibou8

Community Answer

When you are doing a linear interpolation, you are approximating the function between points as a line. From there, you can find the estimated value at any point between them. Therefore, you cannot ask the interpolation of a single number - rather, you need multiple numbers to determine your line, and from there you can ask what value you would expect at a point.